I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer: 79 easy do 14x5 then add 9 which equals 79
You need to make both numbers the same denominator (bottom number). Do this by multiplying. So for the first question you need 15 as the denominator. 3x3=9 5x3=15 first one is 9/15. Then its 1x5=5 and 3x5=15. Then you add 9+5 to get 14. The denominator stays the same. 14/15. This cannot be reduced. If reduced, you would be able to divide both numbers by the same number.
1. 14/15
2. 5/6
3. 1/2
4. 13/24
5. 13/24
6. 9/10
7. 5/9
8. 11/35
9. 5/8
10. 1/2
Answer:
do you have pictures that I can see
Answer:
true
Step-by-step explanation:
