The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
#SPJ1
Answer:
8
Step-by-step explanation:
4+4=8
Answer:
Step-by-step explanation:
The Answer is
D) The rate of change for function B is greater than the rate of change for function A.
Answer:
x= 1
y= -3
Step-by-step explanation:
multiply them to get common factor for y or x:
3(7y+10x=-11)
10(4y-3x=-15)
21y+30x=-33
40y-30x=-150 <em>x's cancel out so solve for y</em>
61y = -183
/61 /61
y = -3 <em> insert y into either equation and solve for x</em>
<em />
<em>4(-3) -3x=-15</em>
<em>x = 1</em>
