summarize the method for finding the measure of the hypotenuse of a right triangle if you are given the measure of both legs
1 answer:
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I believe it's<span> 8cos(x)⁸ - 16cos(x)⁶ + 10cos(x)⁴ - 2cos(x)².
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Alternately, you can write [</span><span><span>1 / (tan(2x) - cot(2x))] + [cos(8x) / (tan(2x) - cot(2x))].
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Alternately, you can write [</span><span><span>1 / (tan(2x) - cot(2x))] + [cos(8x) / (tan(2x) - cot(2x))].
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By taking <span>logarithmic of base 10
∴ </span><span>
∴ x log 4 = log 64
∴
∴ The correct choice is
</span><span>x = log base 10 of 64, all over log base 10 of 4</span>