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sveta [45]
3 years ago
14

On a cube, what proportion of the surface area is on each face, to the nearest percent?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0
Cubes have 6 equal faces, and the surface area is the sum of all of these faces. Thus, one face would be 1/6 of the cube's surface area, or about 17%.
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- Shelia went snowboarding. She spent $118
krok68 [10]

Answer: 78.8%

Step-by-step explanation:

Snowboarding was $118= pass + rental

rental was $25, therefore pass will be $118-$25= $93

To get the percentage

93/118 ×100

4 0
3 years ago
Read 2 more answers
The sum of two numbers is 20, and the difference is 40
Feliz [49]

x+y=20\\\underline{x-y=40}\\2x=60\\x=30\\\\30+y=20\\y=-10

<u>-10 and 30</u>

3 0
3 years ago
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I WILL MARK BRAINLIEST IF YOU CAN ANSWER THISSSS (9x10)/44+pi = xy what is xy and how did you find your answer?? After typing pl
melomori [17]

Answer:  1.9

Step-by-step explanation:

You want to multiply 9x10 which is 90.

Then you want to add 44+pi

now pi can be shown as 3.14 or 22 over 7

in this case you want to add 44 + 3.14 which gives you 47.14

now you want to divide 90/47.14 which gives you 1.90920661858 or in short

1.9

6 0
2 years ago
For the statement? below, write the claim as a mathematical statement. State the null and alternative hypotheses and identify wh
snow_tiger [21]

Answer:

Option E - sigma greater than or equal to $327

Step-by-step explanation:

In this question, we are testing whether the standard deviation of the base price of a certain type of all-terrain vehicle is at least $327.

Now, standard deviation is denoted by the symbol sigma(σ). Since the test is saying it should be at least $327, it means it should either be equal to $327 or greater than $327.

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Thus, the claim as a mathematical statement would be;

sigma greater than or equal to $327

5 0
3 years ago
Together, Sarah's two cats have the same mass as her dog, 11 kg. The mass of one cat is
levacccp [35]
First, lets do all calculations in kg. 1kg=1000 grams
Lets set 1 cat's mass as x.
Lets set the other cat's mass as y.
1) x+y=11
2) y=x+1.5   

Lets plug eq 2 into eq 1.
x+x+1.5=11
2x+1.5=11
2x=9.5
x=4.75 kg

If one cat weighs 4.75 kg, then the other must weigh 6.25 kg.




6 0
3 years ago
Read 2 more answers
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