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Tomtit [17]
3 years ago
8

An advertising balloon shaped like a giant soda can is 15 feet tall and 7 feet wide. How many cubic feet of helium will be neede

d to fully inflate the balloon?
Physics
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

576.975 cubic feet of helium will be needed to fully inflate the balloon

Explanation:

To determine how many cubic feet of helium will be needed to fully inflate the balloon, we will determine the volume of the balloon.

From the question,

The balloon is shaped like a giant soda can.

A giant soda can is cylindrical.

Hence, we can determine the volume of the balloon shaped like a giant soda can by using the formula for finding the volume of a cylinder.

The formula for finding the volume of a cylinder is

V = πr²h

Where V is the volume of the cylinder

π is a constant (Take π = 3.14)

r is the radius of the cylinder

and h is the height of the cylinder

From the question, the balloon is 15 feet tall and 7 feet wide

Hence,

Height, h = 15 feet

Width = 7 feet

(NOTE: The width of a cylinder is the same as the diameter)

Then, diameter = 7 feet

Radius, r is given by

Radius = Diameter / 2

Then, Radius = 7 feet / 2 = 3.5 feet

∴ Radius, r = 3.5 feet

Now, for the volume of the balloon,

V = πr²h

V = 3.14 × (3.5)² × 15

V = 3.14 × 12.25 × 15

V = 576.975 cubic feet

This is the volume of the balloon.

Hence, 576.975 cubic feet of helium will be needed to fully inflate the balloon.

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A cube of side 3.56 cm has a charge of 9.11 μ C placed at its center. Calculate the electric flux through one side of the cube
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A 1 kg mass is attached to a spring with spring constant 7 Nt/m. What is the frequency of the simple harmonic motion? What is th
Scorpion4ik [409]

1. 0.42 Hz

The frequency of a simple harmonic motion for a spring is given by:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

k = 7 N/m is the spring constant

m = 1 kg is the mass attached to the spring

Substituting these numbers into the formula, we find

f=\frac{1}{2\pi}\sqrt{\frac{7 N/m}{1 kg}}=0.42 Hz

2. 2.38 s

The period of the harmonic motion is equal to the reciprocal of the frequency:

T=\frac{1}{f}

where f = 0.42 Hz is the frequency. Substituting into the formula, we find

T=\frac{1}{0.42 Hz}=2.38 s

3. 0.4 m

The amplitude in a simple harmonic motion corresponds to the maximum displacement of the mass-spring system. In this case, the mass is initially displaced by 0.4 m: this means that during its oscillation later, the displacement cannot be larger than this value (otherwise energy conservation would be violated). Therefore, this represents the maximum displacement of the mass-spring system, so it corresponds to the amplitude.

4. 0.19 m

We can solve this part of the problem by using the law of conservation of energy. In fact:

- When the mass is released from equilibrium position, the compression/stretching of the spring is zero: x=0, so the elastic potential energy is zero, and all the mechanical energy of the system is just equal to the kinetic energy of the mass:

E=K=\frac{1}{2}mv^2

where m = 1 kg and v = 0.5 m/s is the initial velocity of the mass

- When the spring reaches the maximum compression/stretching (x=A=amplitude), the velocity of the system is zero, so the kinetic energy is zero, and all the mechanical energy is just elastic potential energy:

E=U=\frac{1}{2}kA^2

Since the total energy must be conserved, we have:

\frac{1}{2}mv^2 = \frac{1}{2}kA^2\\A=\sqrt{\frac{m}{k}}v=\sqrt{\frac{1 kg}{7 N/m}}(0.5 m/s)=0.19 m

5. Amplitude of the motion: 0.44 m

We can use again the law of conservation of energy.

- E_i = \frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2 is the initial mechanical energy of the system, with x_0=0.4 m being the initial displacement of the mass and v_0=0.5 m/s being the initial velocity

- E_f = \frac{1}{2}kA^2 is the mechanical energy of the system when x=A (maximum displacement)

Equalizing the two expressions, we can solve to find A, the amplitude:

\frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2=\frac{1}{2}kA^2\\A=\sqrt{x_0^2+\frac{m}{k}v_0^2}=\sqrt{(0.4 m)^2+\frac{1 kg}{7 N/m}(0.5 m/s)^2}=0.44 m

6. Maximum velocity: 1.17 m/s

We can use again the law of conservation of energy.

- E_i = \frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2 is the initial mechanical energy of the system, with x_0=0.4 m being the initial displacement of the mass and v_0=0.5 m/s being the initial velocity

- E_f = \frac{1}{2}mv_{max}^2 is the mechanical energy of the system when x=0, which is when the system has maximum velocity, v_{max}

Equalizing the two expressions, we can solve to find v_{max}, the maximum velocity:

\frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2=\frac{1}{2}mv_{max}^2\\v_{max}=\sqrt{\frac{k}{m}x_0^2+v_0^2}=\sqrt{\frac{7 N/m}{1 kg}(0.4 m)^2+(0.5 m/s)^2}=1.17 m/s m

4 0
3 years ago
Read 2 more answers
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