What force would be required to accelerate a 1.100 kg car to 0,5 m/s27

What is the resultant of two displacement vectors having the same direction? Question 6 options: The resultant is the sum of the

Slav-nsk [51]

The resultant of two displacement vectors having the same direction is the sum of the two displacements having the same direction as the original vectors, therefore the correct answer is option A

<h3>What is a vector?</h3>

Geometrical objects with magnitude and direction are called vectors. A line with an arrow pointing in its direction can be used to represent a vector, and the length of the line corresponds to the vector's magnitude. As a result, vectors are depicted as arrows and have starting and ending points. Physical quantities like displacement, velocity, acceleration, etc. are represented by vectors.

The tail and head of a vector, respectively, are the initial and terminal points of the vector. The transfer of an object from one location to another is described by vectors. Ordered pairs can be used to represent vectors in the cartesian coordinate system.

Thus, The sum of two displacements with the same direction as the original vectors is the result of two displacements with the same direction, so option A is the correct answer.

Learn more about vectors from here

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4 0

2 years ago

A boy of 50 kg jumps off a boat (30 kg), causing the boat to move to the right at 2.0 m/s. In what direction and at what velocit

LUCKY_DIMON [66]

By Newtons Third law this is an action reaction pair of force
So the momentum is the same
30*20=50*x where x is velocity
x= 12m/s
direction is towards left since they act in opposite directions

8 0

3 years ago

Read 2 more answers

If m2 =3kg and m1 = 2 kg, what would be the acceleration? (g = 10 m/s/s)

Liono4ka [1.6K]

Answer:

Explanation: If m2 =3kg and m1 = 2 kg, what would be the acceleration? (g = 10 m/s/s)

A. 5m/s/s

B. 10m/s/s

Answer:

Explanation

C. 6m/s/s

D.4m/s/s

6 0

3 years ago

A 50.0 mg sample of an unknown radioactive substance was placed in storage and its mass measured periodically. After 19.7 days,

PilotLPTM [1.2K]

<h2>Answer: 4.928 days </h2><h2 />

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u></u>

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=3.13mg$ is the final amount of the material

$A_{o}=50mg$ is the initial amount of the material

$t=19.7days$ is the time elapsed

$h$ is the half life of the material (the quantity we are asked to find)

Knowing this, let's substitute the values and find $h$ from (1):

$3.13mg=(50mg)2^{\frac{-19.7days}{h}}$ (2)

$\frac{3.13mg}{50mg}=2^{\frac{-19.7days}{h}}$ (3)

Applying natural logarithm in both sides:

$ln(\frac{3.13mg}{50mg})=ln(2^{\frac{-19.7days}{h}})$ (4)

$-2.77=-\frac{19.7days}{h}ln(2)$ (5)

Clearing $h$ :

$h=\frac{-19.7days}{-2.77}(0.693)$ (6)

Finally:

$h=4.928days$

6 0

3 years ago

What is the density of ocean water if 308.19g fills a 300mL container?

mojhsa [17]

Answer:

Density = 1027.3 [kg/m3]

Explanation:

To solve this problem we must use the concept of density which is defined as the relationship between mass and volume, which can be determined by the following equation.

density = m/v

m = mass = 308.19 [gramm] = 0.30819 [kg]

v = volume = 300 [mL] = 0.3 [Lt] = 0.0003 [m3]

density = (0.30819/0.0003)

density = 1027.3 [kg/m3]

4 0

3 years ago