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Alex_Xolod [135]
3 years ago
6

What happens to energy lost during a transformation

Physics
1 answer:
mash [69]3 years ago
5 0
ANSWER:


Energy loss



EXPLANATION:

When energy is transformed from one form to another, or moved from one place to another, or from one system to another there is some energy loss. This means that when energy is converted to a different form, some of the input energy is turned into a highly disordered form of energy, like heat.Sep 18, 2015
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A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
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Answer:

The average emf that will be induced in the wire loop during the extraction process is 37.9 V

Explanation:

The average emf induced can be calculated from the formula

Emf = -N\frac{\Delta \phi}{\Delta t}

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The change in magnetic flux is given by

\Delta \phi = \phi _{f} - \phi _{i}

Where \phi _{f} is the final magnetic flux

and \phi _{i} is the initial magnetic flux

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\phi = BAcos(\theta)

Where B is the magnetic field

A is the area

and \theta is the angle between the magnetic field and the area.

Initially, the magnetic field and the area are pointed in the same direction, that is, \theta = 0^{o}

From the question,

B = 1.5 T

and radius = 15.0 cm = 0.15 m

Since it is a circular loop of wire, the area is given by

A = \pi r^{2}

∴ A = \pi (0.15)^{2}

A = 0.0225\pi

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\phi_{i}  = (1.5)(0.0225\pi)

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\phi_{i}  = 0.03375\pi Wb

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The field pointed upwards, that is \theta = 90^{o}. Since cos (90^{o}) = 0

Then

\phi_{f} = 0

Hence,

\Delta \phi = 0- 0.03375\pi

\Delta \phi = - 0.03375\pi

From the question

\Delta t = 2.8 ms = 2.8 \times 10^{-3} s

Here, N = 1

Hence,

Emf = -N\frac{\Delta \phi}{\Delta t} becomes

Emf = -(1)\frac{-0.03375\pi}{2.8 \times 10^{-3} }

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Hence, the average emf that will be induced in the wire loop during the extraction process is 37.9 V.

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