Calcium Phospate formula: Ca3(PO4)2
Atomic weight:
Ca = 40 ; P = 31 ; O = 16
Ca3 = 40 * 3 = 120
P = 31
O4 = 16 * 4 = 64
(PO4)2 = (31 + 64) * 2 = 95 * 2 = 190
Ca3(PO4)2 = 120 + 190 = 310 g/mol
31/310 = 10% P in the calcium phospate
1.00kg * 1000 g/kg = 1000 g of phosphorus.
1000 g / 10% = 10,000 g of calcium phosphate
10,000 g / 58.5% = 17,094 grams of ore.
The minimum mass of the ore should be 17,094 grams or 17.094 kg.
Sr N(e⁻)=38
Sr²⁺ N(e⁻)=38-2=36
36e⁻
Answer: The rate of appearance of
is 
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of HBr =
= ![\frac{1d[H_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BH_2%5D%7D%7Bdt%7D)
Rate in terms of appearance of
= ![\frac{1d[Br_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BBr_2%5D%7D%7Bdt%7D)
![-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BHBr%5D%7D%7B2dt%7D%3D%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
Given :
![-\frac{1d[HBr]}{dt}=0.140Ms^{-1}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BHBr%5D%7D%7Bdt%7D%3D0.140Ms%5E%7B-1%7D)
The rate of appearance of
;
![\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BBr_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1d%5BHBr%5D%7D%7B2dt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.140%3D0.0700Ms%5E%7B-1%7D)
Thus rate of appearance of
is 
Matter is predominantly know to exist in three states-
-Solid
-Liquid
-Gas
The three states can be interconverted at appropriate temperature and pressure conditions. Each state exhibits unique properties which are influenced by the intermolecular forces that hold the atoms together in these states.
Ans: Thus, Every time matter changes from a liquid to a gas, the matter also experiences a change in the <u>state (or phase)</u>