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r-ruslan [8.4K]
3 years ago
14

Identify the missing numbers below to show the result of dividing the numbers 5.6 x 10^12 / 3.5 x 10^9 = A x 10^B

Chemistry
1 answer:
KiRa [710]3 years ago
8 0

Answer:

A = 1.6

B = 3

Explanation:

When you are dividing exponents, you subtract them:

10^12 / 10^9 = 12 - 9 = 3

10³ would be the exponent

5.6/3.5 = 1.6

So, 1.6(10³) would be your answer.

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Whose main job is to break down sugar to release energy that a plant cell can use?
Tasya [4]

Answer:

The Mitochondria

Explanation:

Mitochondria are membrane-bound cell organelles that generate most of the energy required to power the cell's organic chemistry reactions. Energy created by the mitochondria is kept in a tiny molecule known as  adenosine triphosphate (ATP).

3 0
3 years ago
determine the ph of a buffer that is 0.55 M HNO2 and 0.75 M KNO2. tha value of Ka for HNO2 is 6.8*10^-4
Mariana [72]

Answer:

pH = 3.3

Explanation:

Buffer solutions minimize changes in pH when quantities of acid or base are added into the mix. The typical buffer composition is a weak electrolyte (wk acid or weak base) plus the salt of the weak electrolyte. On addition of acid or base to the buffer solution, the solution chemistry functions to remove the acid or base by reacting with the components of the buffer to shift the equilibrium of the weak electrolyte left or right to remove the excess hydronium ions or hydroxide ions is a way that results in very little change in pH of the system. One should note that buffer solutions do not prevent changes in pH but minimize changes in pH. If enough acid or base is added the buffer chemistry can be destroyed.

In this problem, the weak electrolyte is HNO₂(aq) and the salt is KNO₂(aq). In equation, the buffer solution is 0.55M HNO₂ ⇄ H⁺ + 0.75M KNO₂⁻ . The potassium ion is a spectator ion and does not enter into determination of the pH of the solution. The object is to determine the hydronium ion concentration (H⁺) and apply to the expression pH = -log[H⁺].

Solution using the I.C.E. table:

              HNO₂ ⇄    H⁺   +   KNO₂⁻

C(i)        0.55M       0M      0.75M

ΔC            -x            +x          +x

C(eq)  0.55M - x       x     0.75M + x    b/c [HNO₂] / Ka > 100, the x can be                                    

                                                             dropped giving ...

           ≅0.55M        x       ≅0.75M        

Ka = [H⁺][NO₂⁻]/[HNO₂] => [H⁺] = Ka · [HNO₂]/[NO₂⁻]

=> [H⁺] = 6.80x010⁻⁴(0.55) / (0.75) = 4.99 x 10⁻⁴M

pH = -log[H⁺] = -log(4.99 x 10⁻⁴) -(-3.3) = 3.3

Solution using the Henderson-Hasselbalch Equation:

pH = pKa + log[Base]/[Acid] = -log(Ka) + log[Base]/[Acid]

= -log(6.8 x 10⁻⁴) + log[(0.75M)/(0.55M)]

= -(-3.17) + 0.14 = 3.17 + 0.14 = 3.31 ≅ 3.3

3 0
3 years ago
Chlorine has two isotopes, 35Cl and 37Cl; 75.77 % of chlorine is 35Cl and 24.23 % is 37Cl. The atomic mass of 35Cl is 34.969 amu
storchak [24]

Answer:

35.4528731 amu

Explanation:

To appropriately get the atomic mass unit of chlorine, we can get the answer using the masses from the isotopes. This can be obtained as follows. What we do is that we multiply the percentage compositions by the masses.

Now let’s do this.

[75.77/100 * 34.969] + [24.23/100 * 36.966]

= 26.4960113 + 8.9568618 = 35.4528731

3 0
3 years ago
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What is the name of the element that has an atomic number of 8?
12345 [234]
Oxygen is the element
3 0
3 years ago
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What happens to the rate of a reaction as the reaction progresses?
ZanzabumX [31]

Answer:

D. The rate decreases as reactants are used up.

Explanation:

Initially, the rate increases until the reaction is at equilibrium. At equilibrium, the rate is constant.

As the reaction progresses, the rate decreases to zero when reactants are used up ( for irriversible reactions only )

3 0
3 years ago
Read 2 more answers
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