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r-ruslan [8.4K]
3 years ago
14

Identify the missing numbers below to show the result of dividing the numbers 5.6 x 10^12 / 3.5 x 10^9 = A x 10^B

Chemistry
1 answer:
KiRa [710]3 years ago
8 0

Answer:

A = 1.6

B = 3

Explanation:

When you are dividing exponents, you subtract them:

10^12 / 10^9 = 12 - 9 = 3

10³ would be the exponent

5.6/3.5 = 1.6

So, 1.6(10³) would be your answer.

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GrogVix [38]

Answer:

extended structure

Explanation:

7 0
3 years ago
Read 2 more answers
What is the concentration of an unknown Mg(OH)2 solution if it took an average of 15.4mL of
vova2212 [387]

Answer:

0.077M

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2HCl + Mg(OH)2 —> MgCl2 + 2H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 2

The mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

Concentration of base Cb =...?

Volume of base (Vb) = 10mL

Concentration of acid (Ca) = 0.1M

Volume of acid (Va) = 15.4mL

Step 3:

Determination of the concentration of the base, Mg(OH)2.

The concentration of the base can be obtained as follow:

CaVa/CbVb = nA/nB

0.1 x 15.4 /Cb x 10 = 2/1

Cross multiply to express in linear form

Cb x 10 x 2 = 0.1 x 15.4

Divide both side by 10 x 2

Cb = (0.1 x 15.4) /(10 x 2)

Cb = 0.077M

Therefore, the concentration of the base, Mg(OH)2 is 0.077M

7 0
3 years ago
Which shell are the valence electrons of a germanium atom in the ground state located
yKpoI14uk [10]
It would be in the fourth shell.
7 0
3 years ago
if an element [x] contains 8 protons, 8 neutrons and 8 electrons, the atomic number of the element is ?
Kaylis [27]

Answer:

8

Explanation:

The atomic number refers to the number which identifies the element, which is the proton number.

7 0
3 years ago
The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i
german
The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.
5 0
3 years ago
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