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soldier1979 [14.2K]
3 years ago
7

Give the number of significant figures in this number: 40

Chemistry
2 answers:
lubasha [3.4K]3 years ago
8 0
The # 4 is the only significant # in 400.. Trailing 0's r not significant unless there is a decimal.

in 0.7000, there are 4 significant #'s.

Kipish [7]3 years ago
3 0
The amount of significant figures is 1
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1 Srcl (aq) + 1 H,60,(aq) → 2 HCl(aq) + 1 Srso (s)
Mrac [35]

Answer:

Mass = 245.72 g

Explanation:

Given data:

Mass of SrCl₂ react = ?

Mass of H₂SO₄ = 300.0 g

Solution:

SrCl₂  +  2H₂SO₄     →     2HCl + Sr(HSO₄)₂

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles =  300.0 g/ 98.079 g/mol

Number of moles = 3.1 mol

Now we will compare the moles of SrCl₂ and  H₂SO₄.

                   H₂SO₄         :       SrCl₂

                        2             :           1

                      3.1             :         1/2×3.1 = 1.55 mol

Mass of SrCl₂:

Mass = number of moles × molar mass

Mass = 1.55 mol × 158.53 g/mol

Mass = 245.72 g

3 0
3 years ago
What gases occur in the same percentages throughout the layers of the atmosphere?
Andrei [34K]
B nitrogen and water vapor<span />
6 0
3 years ago
The larger the molecules of a substance, the the London forces between them. A larger molecule has more electrons and a greater
aev [14]

Answer:

True

Explanation:

All the above statements buttress the fact that the larger molecule, the greater the magnitude of London forces between the molecules. Each of the statements above is a confirmation/explanation of this general rule.

6 0
3 years ago
A equilibrium is the state in which the rate of the forward reaction is _______________ the rate of the reverse reaction.
mrs_skeptik [129]
I believe the blank is (equal).
3 0
2 years ago
Vanadium crystallizes in a body-centered cubic lattice, and the length of the edge of a unit cell is 305 pm. What is the density
Anestetic [448]

Answer:

5.96 g/cm^3

Explanation:

Corner atom = 1/8

Atoms in center = 1

Atoms in face of the cube= 1/2  

Molar mass of V = 50.94 g/mol <em>(from period table)</em>

1 mole = 6.02x10^23

<em>In BCC unit cell:</em>

(8 x 1/8)+ 1=2 per 1 unit cell

<em>Mass: </em>2(50.94g)/6.02x10^23 = 1.69x10^-22 g/unit cell

305pm=(305x10^-12m÷10^-2m) x (1mL÷1cm^3)

           = 2.837 x 10^-23 mL

<em>1pm=10^-12m</em>

<em>1cm=10^-2m</em>

<em>1mL=1cm^3</em>

<em></em>

density=mass/volume

density of V = 1.69x10^-22g÷2.837x10^-23mL

                    =5.957g/mL

                    =5.96g/cm^3

5 0
2 years ago
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