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3 years ago

Using the process of photosynthesis, describe how carbon and oxygen cycles interact

Chemistry

2 answers:

Alex777 [14]3 years ago

8 0

In photosynthesis, plants take in carbon dioxide and turn it into energy that comes out as oxygen.

Helga [31]3 years ago

4 0

During the process of photosynthesis, the plant take in three things:
• sunlight (through the chloroplasts)
• carbon dioxide (under the leaves)
• water (through the roots).

This whole process creates oxygen and glucose. I hope this helps.

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What mass of silver nitrate will react with 5.85 grams of

anygoal [31]

The answer is: 17.0 g
I hope it help!

3 0

3 years ago

Why must all chemical equations be balanced?

Lera25 [3.4K]

If the equation is not balanced, you have extra of one substance. If you try to do an experiment, you could wind up with a totally different outcome. Its kind of like baking a cake. If the ingredients aren't the right amounts, you dont get an edible cake.

8 0

3 years ago

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

3 years ago

1. Solid fossil fuel formed from _____________ remains. Produces energy when _____________.

wolverine [178]

Organisms and burned

7 0

3 years ago

What is more soluble, ammonium chloride or sodium chloride?

vodka [1.7K]

Answer:

Explanation:

When Ammonium Chloride is heated at high temperature, it sublimes and gives rise to white colored dense fumes. ... But, Sodium Chloride does not give rise to any white colored fumes upon heating.

8 0

3 years ago