Answer: Option (3) is the correct answer.
Explanation:
When there is a negative charge on an atom then we add the charge with the number of electrons. Whereas when there is a positive charge on an atom then we subtract the charge from the number of electrons.
Atomic number of chlorine is 17. So, number of electrons present in 
is 17 + 1 = 18 electrons.
Atomic number of cobalt is 27. So, number of electrons present in 
is 27 - 4 = 23 electrons.
Atomic number of iron is 26. So, number of electrons present in 
is 26 - 2 = 24 electrons.
Atomic number of vanadium is 23. So, number of electrons present in V is 23 electrons.
Atomic number of scandium is 21. So, number of electrons present in 
is 21 + 2 = 23 electrons.
Thus, we can conclude that out of the given species, has the greatest number of electrons.
This reaction obeys the law of conservation of mass.
Explanation:
In the burning reaction, methane (CH₄) react with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O):
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Now we calculate the number of moles of methane and carbon dioxide:
number of moles = mass / molar weight
number of moles of methane = 10 / 16.04 = 0.62 moles
number of moles of carbon dioxide = 27 / 44.01 = 0.61 moles
From the chemical reaction we see that 1 mole of methane produces 1 moles of carbon dioxide so 0.6 moles of methane produces 0.6 mole of carbon dioxide. This reaction obeys the law of conservation of mass because the mass of reactants is equal to the mass of products.
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combustion reaction
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Answer:
65,000 g/mol, 43,000g/mol and 22,000 g/mol.
Explanation:
The explanation can be found in the attachment
Answer: b. Clear cutting
Explanation:
Clear cutting is the correct option. Clear cutting involves the clearing up of entire vegetation cover of the region or cutting up of trees. This will lead to loss of canopy cover from a region. This will cause loss of biodiversity of a region as the animals, birds and insects will loose their habitat. Such faunal species may translocate to new region, decrease in number or may extinct.
Answer : The final concentration of copper(II) ion is, 0.198 M
Explanation :
First we have to calculate the moles of 
and 
.
Moles of = Moles of 
= 0.00459 mol
and,
Moles of = Moles of = 0.00869 mol
Now we have to calculate the total moles of copper(II) ion and total volume of solution.
Total moles copper(II) ion = 0.00459 mol + 0.00869 mol
Total moles copper(II) ion = 0.0133 mol
and,
Total volume of solution = 40.6 mL + 26.4 mL = 64.0 mL = 0.067 L (1 L = 1000 mL)
Now we have to calculate the final concentration of copper(II) ion.
Thus, the final concentration of copper(II) ion is, 0.198 M
