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Papessa [141]
3 years ago
13

In the following net ionic equation, identify each reactant as either a Bronsted-Lowry acid or a Bronsted-Lowry base. HCN(aq) H2

O(l) CN-(aq) H3O (aq) B-L _____ B-L _____
The formula of the reactant that acts as a proton donor is_______
The formula of the reactant that acts as a proton acceptor is________
Chemistry
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

Explanation:

The definition of acids and bases by Arrhenius Theory  was modified and extended by  Bronsted-Lowry.

Bronsted-Lowry defined acid as a molecule or ion which donates a proton while a base is a molecule or ions that accepts the proton. This definition can be extended to include acid -base titrations in non-aqueous solutions.

In this theory, the reaction of an acid with a base constitutes a transfer of a proton from the acid to the base.

From the given information:

\mathsf{HCN _{(aq)} + H_2O_{(l)} \to CN^{-}_{(aq)} + H_3O_{(aq)}}

From above:

We will see that HCN releases an H⁺ ion, thus it is a Bronsted-Lowry acid

H_2O accepts the H⁺ ion ,thus it is a Bronsted-Lowry base.

The formula of the reactant that acts as a proton donor is <u>HCN</u>

The formula of the reactant that acts as a proton acceptor is <u>H2O</u>

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Answer:

Evaporation

Explanation:

Evaporation is when liquid becomes a gas which is how the river dried up

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3 years ago
How many moles of KOH are there in 27.5 mL of 0.250 M KOH?
zaharov [31]

Answer:

6.88 × 10^-3mol

Explanation:

Molarity = number of moles (n) ÷ volume (V)

According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:

number of moles = molarity × volume

Volume of KOH = 27.5mL = 27.5/1000

= 0.0275L

n = 0.0275 × 0.250

n = 0.006875 mol

n = 6.88 × 10^-3mol

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3 years ago
My atomic number is 35.453.
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Carbon monoxide (CO) gas reacts with oxygen (O2) gas to produce carbon dioxide (CO2) gas. If 1.00 L of carbon monoxide reacts wi
Lunna [17]
1) Chemical equation:

2CO + O2 ---> 2CO2

2) molar ratios 2 moles CO : 1 mol O2 : 2 moles CO2.

3) When temperature and pressure is kept constant, the molar ratios are equal to the volume ratios.

So, at the same temperature and pressure conditions (standard) you ca state

2 L CO : 1 LO2 : 2 L CO2

=> 2L CO : 2 L CO2 => 1L CO : 1 L CO2.

So, 1 liter of CO2 is produced when 1 liter of CO reacts with excess O2.
7 0
3 years ago
Read 2 more answers
Determine the empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass.
vagabundo [1.1K]

The empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass is C_3H_6S.

<h3>What is the empirical formula?</h3>

An empirical formula tells us the relative ratios of different atoms in a compound.

We need to calculate the number of moles

Number of a mole of carbon =

48.6 g X (\frac{1 mole }{ 12.0107 g}) =4.05 mole

Number of a mole of hydrogen =

8.2g X (\frac{1 mole}{.00784g}) =8.14 mole

Number of moles of sulphur =

43.2g X (\frac{ mole}{32.065g}) = 1.35 mole

Dividing each mole using the smallest number that is divided by 1.35 moles.

Carbon= \frac{4.05 mole }{1.35 mole} =3

Oxygen= \frac{8.14 mole}{1.35 mole} =6

Sulfur= \frac{1.35 mole}{1.35 mole} =1

Empirical formula is C_3H_6S

Learn more about empirical formula here:

brainly.com/question/14044066

#SPJ1

4 0
2 years ago
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