Answer:
11.9 is the pOH of a 0.150 M solution of potassium nitrite.
Explanation:
Solution : Given,
Concentration (c) = 0.150 M
Acid dissociation constant = 
The equilibrium reaction for dissociation of 
(weak acid) is,
initially conc. c 0 0
At eqm. 
First we have to calculate the concentration of value of dissociation constant 
.
Formula used :
Now put all the given values in this formula ,we get the value of dissociation constant .
By solving the terms, we get
No we have to calculate the concentration of hydronium ion or hydrogen ion.
![[H^+]=c\alpha=0.150\times 0.0533=0.007995 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Calpha%3D0.150%5Ctimes%200.0533%3D0.007995%20M)
Now we have to calculate the pH.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
pH + pOH = 14
pOH =14 -2.1 = 11.9
Therefore, the pOH of the solution is 11.9
To determine what gas is this, we use Graham's Law of Effusion where it relates the rates of effusion of gases and their molar masses. We do as follows:
r1/r2 = √(M2 / M1)
Let 1 be the the unkown gas and 2 the H2 gas.
r1/r2 = 0.225
M2 = 2.02 g/mol
0.225 = √(2.02 / M1)
M1 = 39.90 g/mol
From the periodic table of elements, most likely, the gas is argon.
Answer:
You can infert that it has a mass of 40 grams.It also has desnity of 40 grams per millilieter.
Explanation:
You just have to find a conversion from amu to grams. For every 1 amu, there is 1.66×10⁻²⁴ grams. Thus,
Mass of proton = 1.0073 amu * 1.66×10⁻²⁴ grams/amu = 1.672×10⁻²⁴ grams
Since a proton is spherical in shape, the volume would be:
Volume = 1/6*πd³ = 1/6*π(1.0×10⁻¹⁵ cm)³ = 5.236×10⁻⁴⁶ cm³
Therefore, the density is equal to
Density = Mass/Volume = 1.672×10⁻²⁴ grams/5.236×10⁻⁴⁶ cm³
Density = 3.2×10²¹ g/cm³
