Given that we assume that all the bases of the triangles are parallel.
We can use AAA or Angle-Angle-Angle to prove that these triangles are similar.
Each parallel line creates the same angle when intersecting with the same side.
For example:
The bases of each triangle cross the left side of all the triangle.
Each angle made by the intersecting of the the parallel base and the side are the same.
Thus, each corresponding angle of all the triangles are congruent.
If these angles are congruent, then we have similar triangles.
$63.75 in the morning and 21.25 in the afternoon
Answer:
x=13 y=10 z=3 d) 260
Step-by-step explanation:
vertex angles are congruent so you can set them equal to each other and solve
and then a straight like adds up to 180 so 180-(7(x-3)+5y)= your missing angle and then that angles is congruent to its opposite so 2(5z+15)=60
Answer:
42 is an area
Step-by-step explanation:
"AA" and "HH" are the two among the following choices given in the question that are not congruent <span>theorems for right triangles. The correct options among all the options that are given in the question are option "C" and option "E". I hope that this is the answer that has actually come to your help.</span>
