Answer:
Let the coordinate of focus be 
As per the statement: The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide.
⇒Length of Major axis=base of an auditorium = 200 feet and Length of a minor axis=wide of a auditorium = 100 ft
Semi-major axis (a) = 100 ft and
semi-minor axis(b) = 50 ft
Then, by an equation:

Solve for c:
Substitute the given values we have;

Simplify:

or
ft
Distance between the foci is, 
Therefore, the distance between the foci to the nearest 10th of a foot is, 173.2 ft
Answer:
1:2
Step-by-step explanation:
since cats is 3 you put 3 and fish is 6 you put 6
it will equal to 3:6 but in the simplest form, its 1:2
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ:</u></h3>
Here, we area provided a cone with:
- Radius = 48m
- Height = 68 m
We have to find the volume of the cone in feet³, and we are given that 1m = 3.2808ft
<h3><u>Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙ</u><u>ⳑɑ</u><u>:</u></h3>
The volume of a cone is equal to one third of the volume of a cylinder having the same base radius and height ,i.e:

<u>Therefore</u><u>,</u><u> </u><u>Volume:</u>





![\implies\quad \tt { V = 163,983.36 \times (3.2808)^3 \qquad\quad\bigg[ As, \: 1m = 3.2808ft\bigg]}](https://tex.z-dn.net/?f=%20%5Cimplies%5Cquad%20%5Ctt%20%7B%20V%20%3D%20163%2C983.36%20%5Ctimes%20%283.2808%29%5E3%20%5Cqquad%5Cquad%5Cbigg%5B%20As%2C%20%5C%3A%201m%20%3D%203.2808ft%5Cbigg%5D%7D)


ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>volume </u><u>of </u><u>given </u><u>cone </u><u>is </u><u>5,790,806.5</u><u> </u><u>f</u><u>t</u><u>³</u><u>.</u>
Sally types faster than sue per minute by 10 words. If you divide 3000 by 60 because there are 60 minutes in an hour you will get how many words she types a minute which would be 50.
Answer:
9v-18
Step-by-step explanation:
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