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tankabanditka [31]
3 years ago
12

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Mathematics
2 answers:
IgorC [24]3 years ago
4 0

\left\{\begin{array}{ccc}-3x-y+z=6\\-3x-y+3z=0\\x-3z=3&|\text{add 3z to both sides}\end{array}\right\\\\x=3+3z\\\\\text{Substitute it to the first and the second equation:}\\\\\left\{\begin{array}{ccc}-3(3+3z)-y+z=6\\-3(3+3z)-y+3z=0\end{array}\right\\\\\text{use distributive property}\\\\\left\{\begin{array}{ccc}-9-9z-y+z=6&|\text{add 9 to both sides}\\-9-9z-y+3z=0&|\text{add 9 to both sides}\end{array}\right\\\\\text{combine like terms}

\left\{\begin{array}{ccc}-8z-y=15\\-6z-y=9&|\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-8z-y=15\\6z+y=-9\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-2z=6\qquad\text{divide both sides by (-2)}\\.\qquad\boxed{z=-3}\\\\\text{Put the value of z to the second equation:}\\\\6(-3)+y=-9\\-18+y=-9\qquad\text{add 18 to both sides}\\\boxed{y=9}\\\\\text{Put the value of z to the equation}\ x=3+3z:\\\\x=3+3(-3)\\x=3-9\\\boxed{x=-6}

Answer:\ \boxed{x=-6,\ y=9,\ z=-3\to(-6,\ 9,\ -3)}

mash [69]3 years ago
3 0

Answer:

(-6,9,-3)

Step-by-step explanation:

-3x -y +z=6

-3x-y+3z =0

x-3z =3

Multiply the second equation by -1

-1 *(-3x-y+3z) =0*-1

3x +y -3z =0

Add this to the first equation

-3x -y +z=6

3x +y -3z =0

----------------------

0 + 0 + -2z = 6

Divide by -2

-2z/-2 = 6/-2

z = 6/-2

z=-3


Take the third equation to find x

x-3z=3

x-3(-3) = 3

x+9=3

Subtract 9 from each side

x+9-9 =3-9

x=-6

Now we need to find y

3x +y -3z =0

3(-6) +y -3(-3) =0

-18 +y +9=0

-9+y =0

Add 9 to each side

-9+9+y = 0+9

y=9

(-6,9,-3)

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