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UNO [17]
3 years ago
6

Emma runs 3/4 mile in 6 minutes. Joanie runs 1 1/2 miles in 11 minutes. Whose speed is greater?

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0
Amma solve it first then ill tell you what i got as the answer:)
You might be interested in
A number line that represents k > 5
schepotkina [342]

Answer:

any number from 6 and above

3 0
3 years ago
Pls help you will get brainliest
cupoosta [38]

Answer:

5/6

Step-by-step explanation:

1/6 + 1/6 = 2/6 TYPE A wood

1/4 + 1/4 = 2/4 TYPE B wood

2/6 + 2/4= ...

2/4 reduces to ?/2

That would be 1/2 because 4 divided by 2 is 2 & 2 divided by 2 is 1.

1/2= ?/6

Its 3/6 because we did 2 x 3 to get 6 and we do the same to the number 1. So we do 1 x 3 = 3

Now we have 3/6 + 2/6!

This is very easy now! We just do 2 + 3 which gets 5.

OUR ANSWER IS 5/6!! Hope this helps! plz mark as brainliest!

8 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
Alexus [3.1K]

Answer:

10 - p  is his change

Step-by-step explanation:

hope this helps

3 0
2 years ago
What is the total surface area?? Please help me I’m confused
Simora [160]

Answer:

216

Step-by-step explanation:

8 0
3 years ago
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