Answer:
D. He showed that most of an atom's mass was located in the atom's
nucleus.
Explanation:
Ernest Rutherford changed the atomic model because of his experiment which was the gold foil experiment. A beam of alpha particles was aimed at a piece of gold foil, most particles passed through but some were scattered backward which showed that the middle of an atom (nucleus) is the where most of the mass is located.
Through manipulation of equations, we are able to obtain the equation:
![-pOH= log [ OH^{-}]](https://tex.z-dn.net/?f=-pOH%3D%20log%20%5B%20OH%5E%7B-%7D%5D%20)
Then we can transform the equation into:
![[ OH^{-}]= 10^{-pOH}](https://tex.z-dn.net/?f=%5B%20OH%5E%7B-%7D%5D%3D%2010%5E%7B-pOH%7D%20%20)
Then we are able to plug in the pOH and directly get [OH-]:
![[ OH^{-}] = 10^{-6.48}](https://tex.z-dn.net/?f=%5B%20OH%5E%7B-%7D%5D%20%3D%2010%5E%7B-6.48%7D%20)
![[ OH^{-}]=3.31* 10^{-7} M](https://tex.z-dn.net/?f=%5B%20OH%5E%7B-%7D%5D%3D3.31%2A%2010%5E%7B-7%7D%20M%20%20)
10H₂ + 5O₂ → 10H₂O
Explanation:
This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:
"In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".
This meaning of this is that; the number of atoms on each side of the expression must be the same.
2H₂ + O₂ → 2H₂O
let us check is the equation above is balanced;
2H₂ + O₂ → 2H₂O
Elements reactant product
H 4 4
O 2 2
We can see vividly that the equation is balanced;
Now; if we have 5 oxygen gas, we multiply the equation through by 5:
5 x ( 2H₂ + O₂ → 2H₂O )
⇒ 10H₂ + 5O₂ → 10H₂O
Elements reactant product
H 20 20
O 10 10
learn more:
Balanced equation brainly.com/question/11102790
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Answer:
0.50 M
Explanation:
Given data
- Mass of sodium sulfate (solute): 7.1 g
- Volume of solution: 100 mL
Step 1: Calculate the moles of the solute
The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:
Step 2: Convert the volume of solution to liters
We will use the relation 1 L = 1000 mL.
Step 3: Calculate the molarity of the solution
