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Sidana [21]
1 year ago
13

The element with a completely filled p-subshell is:

Chemistry
1 answer:
tigry1 [53]1 year ago
4 0

The element with the completely filled p-subshell is Ar (Option C)

<h3>What is electronic configuration?</h3>

This is the arrangement of elecartons in the atomic orbitals of an element. The modern electronic configuration makes use of the s, p, d, f orbital notation where

  • Sharp (s) = Maximum of 2 electrons
  • Principal (p) = Maximum of 6 electrons
  • Diffuse (d) = Maximum of 10 electrons
  • Fundamental (f) = Maximum of 14 electrons

<h3>How to determine the element with the completely filled p-orbital</h3>

To obtain the correct answer, we shall write the electronic configuration of each element given in the question. This is illustrated below

  • Na (11) => 1s² 2s²2p⁶ 3s¹
  • P (15) => 1s² 2s²2p⁶ 3s²3p³
  • Ar (18) => 1s² 2s²2p⁶ 3s²3p⁶
  • Al (12) => 1s² 2s²2p⁶ 3s²

From the above illustrations, we can see that only Ar has completely filled p-subshell.

Thus, Ar (Option C ) is the correct answer to the question

Complete question

See attached photo

Learn more about electronic configuration:

brainly.com/question/14283892

#SPJ12

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Here we make use of the Clausius-Clapeyron equation;

ln\left (\frac{p_{2}}{p_{1}}  \right )=-\frac{\Delta H_{vap}}{R}\cdot \left (\frac{1}{T_{2}}-\frac{1}{T_{1}}  \right )

Where:

P₁ = 1 atm =The substance vapor pressure at temperature T₁ = 282°C = 555.15 K

P₂ = 0.2 atm = The substance vapor pressure at temperature T₂

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R = The universal gas constant = 8.314 J/K·mol

Plugging in the above values in the Clausius-Clapeyron equation, we have;

ln\left (\frac{0.2}{1}  \right )=-\frac{28.5 \times 10^3}{8.3145}\cdot \left (\frac{1}{T_{2}}-\frac{1}{555.15}  \right )

\therefore T_2 = \frac{-3427.95}{ln(0.2)-6.175}

T₂ = 440.37 K

To convert to Celsius degree temperature, we subtract 273.15 as follows

T₂ in °C = 440.37 - 273.15 = 167.22 °C

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