All categories

3 years ago

What do dipole-dipole forces do?

Chemistry

2 answers:

hoa [83]3 years ago

6 0

Answer:

Dipole-dipole forces are weak electrostatic attractions between the positive dipole of one polar molecule and the negative dipole of another.

Explanation:

An example of such forces occurs between the hydrochloric acid molecules.

$H - Cl -----H -Cl$

Dipole-dipole forces are represented with dotted lines.

g100num [7]3 years ago

3 0

An ion-dipole force is a type of intermolecular force in which forces of attraction or repulsion occur between neighboring ions, molecules or atoms.

You might be interested in

What is a zero order reaction? Give two examples.

dezoksy [38]

Answer:

I guess 3 to be honest and that's what I think

4 0

3 years ago

Which of the following statements is FALSE?

Alborosie

Answer:

The answer to your question is: letter E

Explanation:

A. This option is correct, the n = 3 shell only has subshells: s, p and d, and shell n = 4 or 5 have f subshell.

B. This option is true in subshell p could be at most 6 electrons and 3 suborbitals.

C. This option is correct orbital "s" is a sphere.

D. This option is correct, in subshell d could be at most 10 electrons and 5 orbitals.

E. This option is false, hydrogen only has 1 electron and then one subshell (s).

6 0

3 years ago

Calculate the maximum numbers of moles and grams of H₂S that can form when 158 g of aluminum sulfide reacts with 131 g of water:

Phantasy [73]

What is Chemical Reaction?

A chemical reaction is the chemical transformation of one set of chemical components into another.

Main Content

Mass of aluminium sulfide is 158g

Mass of water is 131g

The chemical reaction: $Al_{2}S_{3} +H_{2}O _\to Al(OH)_{3} + H_{2}S$

First, balance the chemical equation

$Al_{2}S_{3} + 6H_{2}O \to 2Al(OH)_{3} + 3H_{2}S$

Aluminium sulfide has a molar mass of 150.16 g/mol and water has a molar mass of 18.02 g/mol. As a result, the moles of aluminum sulfide are computed as follows:

$n_{Al_{2}S_{3} } = \frac{Mass}{Molar mass}\\n_{Al_{2} S_{3} } = \frac{158g}{150.16g/mol} \\n_{Al_{2}S_{3} }=1.05 mol$

From the chemical reaction , the ratio of molar is 3mol $H_{2}S/1 mol Al_{2}S_{3}.$ So, the moles of hydrogen sulfide are:

$n_{H_{2} O} =\frac{131g}{18.02g/mol}$

= 7.26mol

From the chemical reaction, the molar ratio is 3 mol $H_{2}S/6$ mol $H_{2}O.$ So, the moles of hydrogen sulfide are:

Moles of $H_{2}S$ formed = 7.26 mol $H_{2}O \times \frac{3 mol H_{2}S }{6 mol H_{2} O} }$

Th liming reactant is $Al_{2}S_{3}$ beacuse the mass of $Al_{2}S_{3}$ forms less product than water. Therefore, the maximum number of moles of $H_{2}S$ is 3.15 mol. We know that molar mass of $H_{2}S$ is 34.10g/mol. So, the maximum mass of $H_{2}S$ formed is,

$m_{H_{2}S } = n_{H_{2}S } \times$ Molar mass of $H_{2}S$

= 3.15 mol $\times$ 34.10g/mol

= 107.4g

Now, multiplying the number of moles of $Al_{2}S_{3}$ by the molar ratio between $Al_2S_3$ and $H_2O$ which is 6mol $H_2O/1mol$ $Al_2S_3$ we get the number of moles of $H_2O$ reacted.