Answer: Two cold air masses surround a warm air mass during a warm front, but a cold air mass moves against a warm air mass during an occluded front.
Boyle's law: in Boyle's law, pressure of a gas in inversely proportional to the volume while the temperature is shield constant
Gay-Lussac's law: In Gay-Lussac's law, pressure of a gas in directly proportional to the temperature while the volume is held constant.
Charles's law: In Charles's law, the volume of a gas is directly proportional to the temperature while the pressure is held constant.
C. is the answer. i know because i had this question not that long ago.
Answer:
V₂ = 946.72 mL
Explanation:
Given data;
Initial pressure = 0.926 atm
Initial volume = 457 mL
Temperature = constant = 29.5°C
Final pressure = 0.447 atm
Final volume = ?
Solution:
The given problem will be solved through the Boyle's law,
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
by putting values,
P₁V₁ = P₂V₂
0.926 atm × 457 mL = 0.447 atm × V₂
V₂ = 423.18 atm. mL/ 0.447 atm
V₂ = 946.72 mL
Answer:
<u>25 to 1 fuel mix 1 gallon</u>
Explanation:
Add two of the 2.5 ounce containers to 1 gallon of gas. For a 50:1 ratio add 1 container 2.5 ounces to 1 gallon of gas. 50=parts of fuel 1=parts of oil . For 25:1 and 2 of the 2.5 oz containers to 1 gallon of gas.
