How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v
1 answer:
The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
where q is the charge of the proton,
, with 
being the elementary charge, and 
and 
are the initial and final voltage.
Substituting, we get (in electronvolts):
and in Joule:
where q is the charge of the proton,
Substituting, we get (in electronvolts):
and in Joule:
You might be interested in
Answer
given,
wavelength (λ) = 650 nm
angle = 5°
using bragg's law
d = 7.46 x 10⁻⁴ cm
number of slits per centimeter
=
b) wavelength of two rays 650 nm and 420 nm
d = 2 x 10⁻6 m
we now,
for 650 nm
θ = 40.54°
for 450 nm
θ = 24.83°
now, difference
|θ_{650} -θ_{420}| =40.54°-24.83°
|θ_{650} -θ_{420}| =19.71°