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NikAS [45]
3 years ago
11

How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v

? express your answer both in joules and electron volts?
Physics
1 answer:
777dan777 [17]3 years ago
5 0
The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
W= qV_i - qV_f
where q is the charge of the proton, q=1 e = 1.6\cdot 10^{-19}C, with e being the elementary charge, and V_i = +125 V and V_f = -55 V are the initial and final voltage.

Substituting, we get (in electronvolts):
W=e(125 V-(-55 V))=180 eV
and in Joule:
W=(1.6 \cdot 10^{-19})(125 V-(-55V))=2.88 \cdot 10^{-17}J

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