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NikAS [45]
3 years ago
11

How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v

? express your answer both in joules and electron volts?
Physics
1 answer:
777dan777 [17]3 years ago
5 0
The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
W= qV_i - qV_f
where q is the charge of the proton, q=1 e = 1.6\cdot 10^{-19}C, with e being the elementary charge, and V_i = +125 V and V_f = -55 V are the initial and final voltage.

Substituting, we get (in electronvolts):
W=e(125 V-(-55 V))=180 eV
and in Joule:
W=(1.6 \cdot 10^{-19})(125 V-(-55V))=2.88 \cdot 10^{-17}J

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Explanation:

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          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

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let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

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measured from the pivot point

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8 0
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A flat coil of wire has an area A, N turns, and a resistance R. It is situated in a magnetic field, such that the normal to the
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Answer:

Johnny created an electromagnet out of a solenoid (a coil of wires with 20 loops), an iron core (of 1 nail), and a single 9 V battery. When Johnny does this, he creates a small magnetic field that allows him to pick up 2 paper clips. Using a CER format, explain to Johnny three things he could change that would increase the strength of his magnetic field and why each change increases the magnetic field. You may want to write three paragraphs to make this easier for the reader to understand

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A parallel plate capacitor stores charge, and thus, stores energy in the form of electric potential energy. The total energy sto
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The charges on the plates,

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4 years ago
3. Force = _____ x _____?
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8 0
3 years ago
One day you are driving your friends around town and you drive quickly around a corner without slowing down. You are going at a
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Answer:

1.60 g

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From the attached file below:

we can deduce that:

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x = vt

x = 20 m/s × 2 s

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The centripetal acceleration can be expressed as:

a = \frac{v^2}{r}

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the magnitude of the acceleration experienced by your unfortunate passengers in terms of acceleration due to gravity is then determined by the equation:

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6 0
4 years ago
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