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Aloiza [94]
3 years ago
14

A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula

r to the disk faces. A uniform force of 4.0 N is applied tangentially to the rim of the disk. What is the angular acceleration of the disk?
Physics
1 answer:
igomit [66]3 years ago
5 0

Answer:

Angular acceleration of the disk will be \alpha =10.714rad/sec^2

Explanation:

We have given mass of the disk m = 5 kg

Diameter of the disk d = 30 cm = 0.3 m

So radius r=\frac{d}{2}=\frac{0.3}{2}=0.15m

Moment of inertia of disk is given by I=\frac{1}{2}mr^2=\frac{1}{2}\times 5\times 0.15^2=0.056kgm^2

Force is given by F=4 N

Torque is given as \tau =Fr=4\times 0.15=0.6N-m

We also know that torque is given by \tau =I\alpha

0.6=0.056\times \alpha

\alpha =10.714rad/sec^2

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