The amount of energy required to raise the temperature of 1 kilogram of a substance by 1 Kelvin is called its
2 answers:
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Answer:
For this ideal Rankine cycle:
A) The rate of heat addition into the cycle Qh is 3214.59KJ/Kg.
B) The thermal efficiency of the system εt=0.4354.
C) The rate of heat rejection from the cycle Qc is 1833.32KJ/Kg.
D) The back work ratio is 0.013
Explanation:
To solve the ideal Rankine cycle we have to determinate the thermodynamic information of each point of the cycle. We will use a water thermodynamic properties table. In an ideal Rankine cycle, the process in the turbine and the pump must be isentropic. Therefore S₃=S₄ and S₁=S₂.
We will start with the point 3:
P₃=18000KPa T₃=550ºc ⇒ h₃=3416.12 KJ/Kg S₃=6.40690 KJ/Kg
Point 4:
P₄=9KPa S₄=S₃ ⇒ h₄=2016.60 (x₄=0.7645 is wet steam)
Point 1:
P₁=P₄ in the endpoint of the steam curve. ⇒ h₁= 193.28KJ/Kg S₁=0.62235KJ/Kg x₁=0
Point 2:
P₂=P₃ and S₂=S₁ ⇒ h₂=201.53KJ/Kg
With this information we can obtain the heat rates, the turbine, and the pump work:
We can answer the questions with this data:
A)
B)
C)
D)
Answer:
The quantity of charge or electron flowing the wire in the given time is 4.5 x 10¹⁹ electrons.
Explanation:
Given;
emf of the battery, V = 12 V
resistance of the resistor, R = 100-Ω
time of current flow, t = 1 min
charge of 1 electron = 1.602 x 10¹⁹ C
The current through this circuit is given by;
I = V / R
I = (12) / (100)
I = 0.12 A
The quantity of charge or electron flowing the wire in the given time is calculated as;
Q =It
where;
I is the current flowing through the wire
t is the time of current flow = 1 x 60s = 60 s
Q = 0.12 x 60
Q = 7.2 C
1.602 x 10⁻¹⁹ C --------------- 1 electron
7.2 C -----------------------------? electron
Therefore, the quantity of charge or electron flowing the wire in the given time is 4.5 x 10¹⁹ electrons.