Answer: 0.006in/s
Explanation:
Let the rate at which air is being blown into a spherical balloon be dV/dt which is 1.68in³/s
Also let the rate at which the radius of the balloon is increasing be dr/dt
Given r = 4.7in and Π = 3.14
Applying the chain rule method
dV/dt = dV/dr × dr/dt
If the volume of the sphere is 4/3Πr³
V = 4/3Πr³
dV/dr = 4Πr²
If r = 4.7in
dV/dr = 4Π(4.7)²
dV/dr = 277.45in²
Therefore;
1.68 = 277.45 × dr/dt
dr/dt = 1.68/277.45
dr/dt = 0.006in/s
The force required to start an object sliding across a uniform horizontal surface is larger than the force required to keep the object sliding at a constant velocity once it starts.
The magnitudes of the required forces are different in these situations because the force of kinetic friction is less than the force of static friction. <em>(d)</em>
Answer:
2.88×10⁻⁹ s
2.40×10¹⁵ m/s²
Explanation:
Given:
v₀ = 12300 m/s
v = 6.92×10⁶ m/s
Δx = 0.997 cm = 0.00997 m
Part 1) Find: t
Δx = ½ (v + v₀)t
0.00997 m = ½ (6.92×10⁶ m/s + 12300 m/s) t
t = 2.88×10⁻⁹ s
Part 2) Find: a
(6.92×10⁶ m/s)² = (12300 m/s)² + 2a (0.00997 m)
a = 2.40×10¹⁵ m/s²
