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julsineya [31]
3 years ago
15

The model that describes a Sun-centered solar system is called theA.laws of motion.B.geocentric model.C.heliocentric model.D.gen

eral theory of relativity.
Physics
1 answer:
artcher [175]3 years ago
7 0
The answer is C the heliocentric model.
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Classify the following situations into contact and non-contact forces.
NARA [144]

Answer: Contact force

a. Applying break in a vehicle.

d. The speed of ball rolling on ground is reduced

Non contact force

b. A coconut falling from a coconut tree.

c. The planets revolving around the sun.

Explanation:

The contact force is the force which exerts when one object or entity comes in contact with other object or entity. For example, on application of break the vehicle stops, the force is applied on the breaks to stop the vehicle. The ball rolling on the ground the speed reduces so the application of force on the ground also reduces.

The non contact force is the force one object exerts on the other without coming in direct contact with the other object. The force exerted by one object on other due to gravity is a non contact force. The coconut falling on the ground and planets revolving around the sun are examples of non contact force due to gravity.

8 0
2 years ago
How to solve this step by step
victus00 [196]
Well, it goes 60 miles in one hour......so set up a ratio.....
60 miles/5 miles = 1 hr/x.....you'll get 60x = 5....then 5/60 would be 0.083 

7 0
2 years ago
You accelerate a 0.43kg football 5m/s2. Calculate the force you applied to the football.
Elza [17]

The force applied on the football is 2.15 Newton.

Given the data in the question;

  • Mass of football; m = 0.43kg
  • Acceleration; a = 5m/s^2

Force applied; F = \ ?

To determine the force applied on the football, we use Newton's laws of motion:

F = m * a

Where m is the mass of the object and a is the acceleration.

We substitute our given values into the equation

F = 0.43kg\ *\ 5m/s^2\\\\F = 2.15kg.m/s^2\\\\F = 2.15N

Therefore, the force applied on the football is 2.15 Newton.

Learn more: brainly.com/question/2388393

7 0
2 years ago
Copper has a modulus of elasticity of 110 GPa. A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm is pull
bearhunter [10]

Answer:

strain = 1.4 \times 10^{-3}

Explanation:

As we know by the formula of elasticity that

E = \frac{stress}{strain}

now we have

E = 110 GPA

E = 110 \times 10^9 Pa

Area = 15.2 mm x 19.1 mm

A = 290.3 \times 10^{-6}

now we also know that force is given as

F = 44500 N

here we have

stress = Force / Area

stress = \frac{44500}{290.3 \times 10^{-6}}

stress = 1.53 \times 10^8 N/m^2

now from above formula we have

strain = \frac{stress}{E}

strain = \frac{1.53 \times 10^8}{110 \times 10^9}

strain = 1.4 \times 10^{-3}

7 0
3 years ago
Magnitudes físicas y sus unidades ; poner a que magnitud pertenece
BARSIC [14]

Answer:

1. Energía = 4 J

2. Fuerza = 1,3 N

3. Aceleración = 2 m/s²

4. Masa = 7,1 kg

Explanation:

Magnitudes físicas y sus unidades;

1. Energía = 4 Joules

Energía se puede definir como la habilidad (capacidad) para realizar un trabajo.

2. Fuerza = 1,3 Newton

Fuerza = masa * aceleración

3. Aceleración = 2 m/s²

Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.

Esto simplemente significa que la aceleración viene dada por la resta de la velocidad inicial de la velocidad final a lo largo del tiempo.

4. Masa = 7,1 Kilograms

La masa se puede definir como una medida de la cantidad de materia de la que se compone un objeto o un cuerpo. La unidad de medida estándar de la masa de un objeto o un cuerpo son los kilogramos.

8 0
2 years ago
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