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motikmotik
2 years ago
14

Where will the strongest force be excerted by the scissor blades to cut through a piece of material? Explain your answer.

Physics
1 answer:
asambeis [7]2 years ago
8 0

Answer:

in the thick part of the scissors ✂️

Explanation:

because in physics simple machine called wedge the force applied in this thick area it have thine side used to split or piece objects

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A strong gust of wind blows an apple off a tree. The apple has a mass of 0.25 kg. The gust of wind pushes the apple with a force
LenKa [72]

Answer:

2.66N

Explanation:

8 0
3 years ago
Read 2 more answers
I need help quickly pls
sukhopar [10]

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

4 0
3 years ago
An airplane pilot sets a compass course due west and maintains a speed of 220 km/h. after flying for a half hour she finds herse
timurjin [86]

The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.  

so airspeed due west is  = net speed - speed of plane = 240-220= 20 km/h.  

airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.  

the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h

the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.  

if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.

so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.  

the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.

5 0
3 years ago
Read 2 more answers
A ball is tossed with a velocity of 10 m/s directed vertically upward from a window located 20 m above the ground. Determine the
marusya05 [52]

Answer:

Explanation:

Given

Initial velocity of ball u=10\ m/s

height of window h=20\ m

Using Equation of motion

y=ut+\frac{1}{2}at^2

where u=initial velocity

t=time

a=acceleration

As ball is already is at a height of 20 m so

Y=ut+\frac{1}{2}at^2+20

Y=10\times t+0.5\times (-9.8)t^2+20

Y=-4.9t^2+10t+20

(b)highest point is obtained at v=0

v^2-u^2=2as

where

v=final velocity

u=initial velocity

a=acceleration

s=displacement

(0)-10^2=2\times (-9.8)\times s

s=\frac{100}{19.6}

s=5.102\ m

Highest Point will be s+20=25.102\ m

(c)Time taken when the ball hit the ground i.e. at Y=0

-4.9t^2+10t+20=0

t=3.28\ s

impact velocity v=\sqrt{2\times 9.8\times 25.102}

v=22.181\ m/s

7 0
3 years ago
An empty can of soda is yeeted (thrown) into a crowd. Then, a full can of soda is yeeted into a crowd. Throwing the full can too
4vir4ik [10]

Answer:

Newton's third law of motion.

Explanation:

We are told the force needed to throw the full soda can was more than that needed to throw the empty can.

Now, the weight of the full soda can will be more than that of the empty can. Therefore, the full can will demand more force than that of the empty can due to Newton's third law of motion which states that to every action, there is an equal and opposite reaction.

3 0
2 years ago
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