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3 years ago

How are power ratings used to describe machines?

Physics

2 answers:

kherson [118]3 years ago

8 0

power ratings basically just compare with how many watts are used, like a tackle in football compares to a car engine

amid [387]3 years ago

7 0

For historical reasons, the horsepower is occasionally used to describe the power delivered by a machine. One horsepower is equivalent to approximately 750 Watts. ... Thus, the power of a machine is the work/time ratio for that particular machine. A car engine is an example of a machine that is given a power rating.

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If you push a crate across a factory floor at constant speed in a constant direction, what is the magnitude of the force of fric

poizon [28]

Answer:

The magnitude of the force of friction equals the magnitude of my push

Explanation:

Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.

Let F = push and f = frictional force and f' = net force

F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0

So, F - f = 0

Thus, F = f

So, the magnitude of the force of friction equals the magnitude of my push.

3 0

3 years ago

A car of mass 1200Kilograms moving at 15 m/s the driver applies the brakes for 0.08 seconds and the castles down to 10 meter per

denpristay [2]

Initial velocity=u=15m/s
Final velocity=v=10m/s
Time=0.08s

$\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf\longmapsto Acceleration=\dfrac{10-15}{0.08}$

$\\ \sf\longmapsto Acceleration=\dfrac{-5}{0.08}$

$\\ \sf\longmapsto Acceleration=-62.5m/s^2$

5 0

3 years ago

A scientist just learned that she will not receive enough money to complete her year-long study about the

Softa [21]

Answer: It's A

conduct smaller studies for more than a one-year period

3 0

3 years ago

Newton's First and Second Laws of Motion:Question 3Kepler-10b, the first confirmed terrestrial extrasolar planet, is about 564 l

OleMash [197]

Answer:

F = 85696.5 N = 85.69 KN

Explanation:

In this scenario, we apply Newton's Second Law:

$Unbalanced\ Force = ma\\Upthrust - Weight\ of\ Space\ Craft = ma\\F - W = ma\\F - mg = ma\\F = m(g + a)\\$

where,

F = Upthrust = ?

m = mass of space craft = 5000 kg

g = acceleration due to gravity on surface of Kepler-10b = (1.53)(9.81 m/s²)

g = 15.0093 m/s²

a = acceleration required = 2.13 m/s²

Therefore,

$F = (5000\ kg)(15.0093\ m/s^{2} + 2.13\ m/s^{2})\\$

8 0

3 years ago

Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then

kari74 [83]

The density of an object is the mass of the object divided by its volume.

Remember that mass of an object is the amount of matter that the object contains. The unit for mas in the standard international unit system is the kilogram (kg), which is 1000 grams; the unit of mass in the US is the pound (lb), which is 453.592 grams.

The volume of an object is the amount of space that the object occupies. The unit for volume in the standard international unit system are the cubic meter ( $m^3$ ) and the liter (L); 1 cubic meter equals 1000 liters.

The density of an object is the quantity of mass of the object per unit of its volume. The unit for mas in the standard international unit system is the kilogram per cubic meter ( $\frac{kg}{m^3}$ ).

Now, lets create our hypothesis:

If the mass and the volume of and object are known, then its density can be calculated dividing the object's mass by its volume.

We can conclude that the density of an object can be obtained by dividing its mass by its volume.

4 0

3 years ago

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