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ankoles [38]
3 years ago
6

How many degenerate orbitals can be found in each p subshell?

Physics
1 answer:
baherus [9]3 years ago
3 0

Answer:

3

Explanation:

For p-subshell we have the value of angular quantum number as l = 1 & the degenerate orbitals are numbered from -l to +l.

  • Therefore here we have -1,0,+1 as the three degenerate orbitals of p subshell.

This is in accordance with the Schrodinger's model that allows the electron to occupy a three dimensional space. It therefore requires three quantum numbers, to describe the orbitals in which electrons can be found. The three coordinates that come from Schrodinger's wave equations are the principal (n), angular (l), and magnetic (m) quantum numbers.

These quantum numbers decide the shape, size and orientation in space of the orbitals on an atom.

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Cheetah mothers perform a number of different behaviors. They and their cubs stay in one place for only four days, moving on bef
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Answer:

Cheetah cubs are in danger from predators like lions and hyenas which can track their prey by scent and so the mother and her cubs leave an area when their scent is too strong so that they are not hunted and the cubs survive.

Mother Cheetahs also train their cubs to hunt so that they may get food for themselves which will ensure their survival as well thus showing that both of these practices can impact on reproductive success.

4 0
3 years ago
What is a element that tends to be shiny, easy shaped, and a good conductor of heat?
ozzi
The answer to your question is Metal
8 0
3 years ago
you are flying on an airplane and you overhear two pasengers comment that flight attendants must be very skiled, one says "when
s344n2d4d5 [400]

How do you get out of a room with only a mirror and a table?

Look in the mirror you see what you saw, use the saw to cut the table, half and half makes a hole, jump in it.

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4 0
3 years ago
A 26.4 g silver ring (cp = 234 J/kg·°C) is heated to a temperature of 66.2°C and then placed in a calorimeter containing 4.94 ✕
Slav-nsk [51]

Answer:

The final temperature of the mixture = 64.834 °C.

Explanation:

Heat lost by the silver ring = heat gained by the water + heat transferred to the surrounding.

c₁m₁(t₁-t₃) = c₂m₂(t₃-t₂) + Q..............Equation 1

Where c₁ = specific heat capacity of the silver copper, m₁ = mass of the silver copper, t₁ = initial temperature of the silver copper, t₃ = final temperature of the mixture. c₂ = specific heat capacity of water, t₂ = initial temperature of water, m₂ = mass of water, Q = energy transferred to the surrounding.

making t₃ the subject of the equation,

t₃ = [c₁m₁t₁+c₂m₂t₂-Q]/(c₁m₁+c₂m₂)........................ Equation 2

Given: c₁ = 234 J/kg.°C, m₁ = 26.4 g, t₁ = 66.2 °C, c₂ = 4200 J/K.°C, m₂ = 4.92×10⁻² kg, t₂ = 24.0 °C, Q = 0.136 J.

Substituting into equation 2

t₃ = [(234×26.4×66.2)+(4200×0.0492×24)-0.136]/[(234×26.4)+(4200×0.0492)]

t₃ = (408957.12+4959.36-0.136)/(6177.6+206.64)

t₃ = (413916.48-0.136)/6384.24

t₃ = 413916.34/6384.24

Thus the final temperature of the mixture = 64.834 °C.

6 0
3 years ago
This is for physics, i need help fast!!
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Speed = distance / time
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