Molarity is the number
of moles of solute in one liter of the solution. Mathematically, M = n/V. Where
Molarity of the solution is M, Number of moles of solute is n, and volume of the
solution is V.
Calculate the mass in
1000 mL of the solution. Density of acetic acid is 1.00 g/mL.
Density = 1.00 g/mL. 1.0
mL has mass 1.00 g. 1000.0 mL has mass = (1000.0 mL/ 1.0 mL) * 1.00 g = 1000.0
g. hence, the mass in 1000.0 mL of the solution if 1000.0 g.
Calculate the mass
contained of 5.00 % acetic acid as follows: 5.00 % of 1040 g = (5.00 / 100) *
1000.0 g = 50.0 g. Hence, the mass contained of 5.00 % acetic acid is
50.0 g.
Calculate the number of moles of acetic acid. Number of
moles = Mass / Molar mass = 50.0 g / 60.0 g/mol = 0.8333 mol. Hence, the number
of moles of acetic acid is 0.8333 mol.
Calculate the molarity of the solution, M = n / V = 0.8333
mol / 1.0 L = 0.8333 M
Therefore, the molarity of the solution if 0.8333 M
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