Answer:
<em>The</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>is</em><em> </em><em>valance</em><em> </em><em>shell</em><em>.</em>
<em>Valance</em><em> </em><em>shell</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>outermost</em><em> </em><em>shell</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>atom</em><em> </em><em>which</em><em> </em><em>contains</em><em> </em><em>valance</em><em> </em><em>electrons</em><em> </em><em>on</em><em> </em><em>it</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>atom</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>elements</em><em>. </em>
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
is the value of the rate constant.
Explanation:

Let the order of the reaction be x.
The rate law of the reaction can be written as:
![R=k[H_2O_2]^x](https://tex.z-dn.net/?f=R%3Dk%5BH_2O_2%5D%5Ex)
1. Rate of the reaction when concentration changes from 0.882 M to 0.697 M in 0 seconds to 60 seconds.

..[1]
2. Rate of the reaction when concentration changes from 0.697 M to 0.566 M in 240 seconds to 360 seconds.

..[2]
[1] ÷ [2]
![\frac{0.00308 M/s}{0.00227 M/s}=\frac{k[0.697 M]^x}{k[0.236M]^x}](https://tex.z-dn.net/?f=%5Cfrac%7B0.00308%20M%2Fs%7D%7B0.00227%20M%2Fs%7D%3D%5Cfrac%7Bk%5B0.697%20M%5D%5Ex%7D%7Bk%5B0.236M%5D%5Ex%7D)
Solving fro x:
x = 0.92 ≈ 1
![R=k[H_2O_2]^1](https://tex.z-dn.net/?f=R%3Dk%5BH_2O_2%5D%5E1)
![0.00308 M/s=k[0.697 M]^1](https://tex.z-dn.net/?f=0.00308%20M%2Fs%3Dk%5B0.697%20M%5D%5E1)
![k=\frac{0.00308 M/s}{[0.697 M]^1}=0.00442 s^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.00308%20M%2Fs%7D%7B%5B0.697%20M%5D%5E1%7D%3D0.00442%20s%5E%7B-1%7D)
is the value of the rate constant.
Nobelium discovered in Berkeley California
Answer:
1. Calcium and fluorine
Symbol Ca F
Charges +2 1−
Formula CaF
2
2. Hydrogen and sulphur
Symbol H S
Charges 1+ 2−
Formula H
2
S
3. Nitrogen and hydrogen
Symbol N H
Charges 3− 1+
Formula NH
3
4. Carbon and chlorine
Symbol C Cl
Charges 4+ 1−
Formula CCl
4
5. Sodium and oxygen
Symbol Na O
Charges 1+ 2−
Formula Na
2
O
6. Carbon and oxygen.
Symbol C O
Charges 4+ 2−
C
2
O
4
i. e.
Formula CO
2
Explanation:
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