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3 years ago

What mass of water is required to react completely with 157.35 g CO2?

Chemistry

2 answers:

dimulka [17.4K]3 years ago

8 0

Answer:64.43g H2O

Explanation: the other one is wrong

motikmotik3 years ago

3 0

Assuming that the question is about making glucose, then you need to know the equation for the reaction. The equation should be:

C6H12O6(s) + 6O2(g) -->6CO2(g) + 6H2O(g)

In this equation, 6 molecules of CO2 would react with 6 molecules of H2O which mean it has 1:1 ratio. The molecular weight for CO2 should be 44g/mole and H2O is 18g/mole. Then the calculation would be: 6/6 * (157.35g/44g) * 18g= 64.37g

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At 25°C, the equilibrium constant Kc for the reaction in thesolvent CCl4 2BrCl <----> Br2 + Cl2 is 0.141. If the initial c

ivolga24 [154]

Answer: The equilibrium concentration of bromine gas is 0.00135 M

Explanation:

We are given:

Initial concentration of chlorine gas = 0.0300 M

Initial concentration of bromine monochlorine = 0.0200 M

For the given chemical equation:

$2BrCl\rightleftharpoons Br_2+Cl_2$

Initial: 0.02 0.03

At eqllm: 0.02-2x x 0.03+x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}$

We are given:

$K_c=0.141$

Putting values in above equation, we get:

$0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135$

Neglecting the value of x = -0.96 because, concentration cannot be negative

So, equilibrium concentration of bromine gas = x = 0.00135 M

Hence, the equilibrium concentration of bromine gas is 0.00135 M

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3 years ago

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inessss [21]

It will have traveled 0.78 m. You find this by multiplying .013 by 60

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Anna007 [38]

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PSYCHO15rus [73]

Answer:

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