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Zanzabum
3 years ago
9

How was the work of Newlands similar to that of Mendeleev on the periodic table?

Chemistry
2 answers:
kiruha [24]3 years ago
8 0
It was similar because  they both arranged the elements in order of increasing atomic mass.
alexdok [17]3 years ago
3 0

Answer:  Elements arranged in atomic weights.

Explanation:   Mendeleev arranged all the elements of the periodic table according to their atomic weights.

Newlands Octaves law also explained that when elements were arranged according to the atomic weights, chemical and physical properties do repeat some kind of trend.

Thus they both worked in arranging the elements in the periodic table considering only the atomic weights as the fundamental and basic property.

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In naming the compound PCl5, the prefix used with the second element is ____________________.
Oksanka [162]

Answer:

\boxed {\boxed {\sf Hepta}}

Explanation:

We are given the formula:

PCl_5

This is a molecular formula, because it contains nonmetals.

1. Name the first element

The first element is phosphorous (P). Since this is the first element and there is only one, we don't need a prefix.

  • Phosphorous

2. Second element

The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of <u>hepta</u>-.

  • Phosphorous heptachlorine

Add the ending of -ide.

  • Phosphorous heptachloride

The prefix used for the second element is hepta. The compound name is phosphorous heptachloride.

6 0
3 years ago
Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G
AnnyKZ [126]
1) Chemical equation

Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag

2) molar ratios

1 mol Cu: 2 moles AgNO3 : 1 mol Cu (NO3)2 : 2 mol Ag

3) Convert 12. 83 * 10^23 atoms of Cu in moles

12.83 * 10 ^ 23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu

4) Use the proportions

2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag

5) Use the atomic mass of silver to convert 4.262 mol in grams

mass = number of moles * atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams

Answer: 459.9 g
5 0
3 years ago
Calculate the free energy change for the reaction:
vova2212 [387]

Answer:

(D) - 16.6 kcal

Explanation:

Hello,

In this case, the Gibbs free energy for the given reaction is computed in terms of the Gibbs free energy of formation of each species involved in the chemical reaction:

\Delta _rG=2\Delta _fG_{NO_2}-2\Delta _fG_{NO}-\Delta _fG_{O_2}

Thus, it is found for nitrogen monoxide, oxygen and nitrogen dioxide the following Gibbs free energies of formation: 87.6, 0 and 51.3 kJ/mol respectively, therefore we compute:

\Delta _rG=2(51.3kJ/mol)-2(87.6kJ/mol)=-72.6kJ*\frac{1kcal}{4.184kJ} \\\\\Delta _rG=-17.35kcal

The closest result is (D) - 16.6 kcal, as such difference is noticed when different sources for thermochemical data are used, in this case, the NIST data were used.

Best regards.

6 0
3 years ago
The blank is a structure in a cell that contains information that controls a cells function​
solong [7]

Answer:

The nucleus

Explanation:

The nucleus controls the metabolic functions of the cell by producing mRNA which encodes for enzymes e.g. insulin. The nucleus controls the structure of the cell by transcribing DNA which encodes for structural proteins such as actin and keratin.

8 0
4 years ago
10. Predict the mass of nitrogen dioxide produced if 2.30 L of ammonia are allowed to react
Scrat [10]

Answer:

Mass of nitrogen dioxide produced = 4.6 g

Explanation:

Given data:

Volume of ammonia = 2.30 L

Mass of nitrogen dioxide produced = ?

Solution:

Chemical equation:

4NH₃ + 7O₂     →      4NO₂ + 6H₂O

Number of moles of ammonia at STP:

PV = nRT

n = PV/RT

n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K

n = 2.30 atm .L / 22.414 atm.L/mol

n = 0.1 mol

Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.

                NH₃            :             NO₂

                 4                :               4

                 0.1             :              0.1

Mass of NO₂:

Mass = number of moles  × molar mass

Mass = 0.1 mol  × 46 g/mol

Mass = 4.6 g

7 0
3 years ago
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