Answer:

Explanation:
We are given the formula:

This is a molecular formula, because it contains nonmetals.
1. Name the first element
The first element is phosphorous (P). Since this is the first element and there is only one, we don't need a prefix.
2. Second element
The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of <u>hepta</u>-.
- Phosphorous heptachlorine
Add the ending of -ide.
- Phosphorous heptachloride
The prefix used for the second element is hepta. The compound name is phosphorous heptachloride.
1) Chemical equation
Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag
2) molar ratios
1 mol Cu: 2 moles AgNO3 : 1 mol Cu (NO3)2 : 2 mol Ag
3) Convert 12. 83 * 10^23 atoms of Cu in moles
12.83 * 10 ^ 23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu
4) Use the proportions
2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag
5) Use the atomic mass of silver to convert 4.262 mol in grams
mass = number of moles * atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams
Answer: 459.9 g
Answer:
(D) - 16.6 kcal
Explanation:
Hello,
In this case, the Gibbs free energy for the given reaction is computed in terms of the Gibbs free energy of formation of each species involved in the chemical reaction:

Thus, it is found for nitrogen monoxide, oxygen and nitrogen dioxide the following Gibbs free energies of formation: 87.6, 0 and 51.3 kJ/mol respectively, therefore we compute:

The closest result is (D) - 16.6 kcal, as such difference is noticed when different sources for thermochemical data are used, in this case, the NIST data were used.
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Answer:
The nucleus
Explanation:
The nucleus controls the metabolic functions of the cell by producing mRNA which encodes for enzymes e.g. insulin. The nucleus controls the structure of the cell by transcribing DNA which encodes for structural proteins such as actin and keratin.
Answer:
Mass of nitrogen dioxide produced = 4.6 g
Explanation:
Given data:
Volume of ammonia = 2.30 L
Mass of nitrogen dioxide produced = ?
Solution:
Chemical equation:
4NH₃ + 7O₂ → 4NO₂ + 6H₂O
Number of moles of ammonia at STP:
PV = nRT
n = PV/RT
n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K
n = 2.30 atm .L / 22.414 atm.L/mol
n = 0.1 mol
Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.
NH₃ : NO₂
4 : 4
0.1 : 0.1
Mass of NO₂:
Mass = number of moles × molar mass
Mass = 0.1 mol × 46 g/mol
Mass = 4.6 g