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4 years ago

This solid is ductile and conducts electricity

Chemistry

1 answer:

AVprozaik [17]4 years ago

8 0

The answer would be a metal, most likely copper. hope this helped (:

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vesna_86 [32]

Milk mixture and heterogeneous

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4 years ago

A certain weak acid, HA, has a Ka value of 2.6×10−7. Calculate the percent ionization of HA in a 0.10 M solution.

Andrej [43]

Answer:

The percent ionization is 0,16%

Explanation:

The percent ionization is defined as the number of ions that exist in a substance.

$PI=\frac{[A-]}{[HA]} x100$

First, we find the [A-] using the ka equation

HA ⇄ $H^{+} + A^{-}$

[H+] = [A-]

$Ka=\frac{[H+][A-]}{[HA]}\\ \\$

since the ionization constant is very small we can assume that the final concentration of [HA] is the same

$Ka=\frac{[H+]^{2} }{[HA]} \\\\$

$[H+]=\sqrt[2]{Ka.[HA]} \\\\$

$[H+] =\sqrt{(2,610^{-7} )(0,1)} = 1,61210^{-4}$

Now we calculate the percent ionization using these values

$PI=\frac{1,61210^{-4} }{0,1} X100$

PI=0,16%

4 0

4 years ago

A rigid container of O 2 has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273°C ?

Vinvika [58]

Answer:

260 kPa

Explanation:

To answer this problem we can use Gay-Lussac's law, which states that at a constant volume (such as is the case with a rigid container):

P₁T₂=P₂T₁

Where in this case:

P₁ = 340 kPa

T₂ = 273 °C ⇒ 273 + 273.16 = 546 K

P₂ = ?

T₁ = 713 K

We input the data:

340 kPa * 546 K = P₂ * 713 K

And solve for P₂:

P₂ = 260 kPa

5 0

3 years ago

Which type of weathering is caused by plants?

alexdok [17]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?

Gnoma [55]

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

4 0

3 years ago