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1 year ago

What is the correct ratio of the atoms of the two elements present in a sample of the compound copper chloride, CuCl2?

1 answer:

8 0

The correct ratio of the atoms of the two elements in the sample of copper chloride compound would be 1:2.

<h3>Atoms of elements</h3>

Copper chloride has a chemical formula, $CuCl_2$ .

Thus, an atom of copper, Cu, combines with 2 atoms of chlorine, Cl.

The 2 chlorine atoms are recipients of an electron each from the copper atom which happens to have 2 electrons in its outermost valence shell.

Therefore, the ratio of copper to chlorine atoms in the compound is 1:2.

More on atoms of elements can be found here: brainly.com/question/15173445

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The molar concentration of $Cu^{2+}$ ions in the given amount of sample is $4.73\times 10^{-5}M$

Explanation:

Given that,

Mass of sample = 21.5 g

0.07 % (m/m) of copper (II) sulfate in plant fertilizer

This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present

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$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

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1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions

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