What is the correct ratio of the atoms of the two elements present in a sample of the compound copper chloride, CuCl2?
1 answer:
The correct ratio of the atoms of the two elements in the sample of copper chloride compound would be 1:2.
<h3>Atoms of elements</h3>Copper chloride has a chemical formula, .
Thus, an atom of copper, Cu, combines with 2 atoms of chlorine, Cl.
The 2 chlorine atoms are recipients of an electron each from the copper atom which happens to have 2 electrons in its outermost valence shell.
Therefore, the ratio of copper to chlorine atoms in the compound is 1:2.
More on atoms of elements can be found here: brainly.com/question/15173445
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[H_{3}O^{+}] = 0.00770 M
The equilibrium equation representing the dissociation of
Given [H_{3}O^{+}] = 0.00770 M
Let the initial concentration of acid be x and change y
So y = =
= 0.00770 M
0.00257 x - 0.00001979 = 0.00005929
x = 0.031 M
Therefore, initial concentration of the weak acid is <u>0.031 M</u>