Answer:
Can you add a picture to your question?
Step-by-step explanation:
Tn = a + (n-1)d
when n = 12, tn = 63
63 = a + (12-1)*5
a = 63 - 55 =8
tn or an
= 8 + (n-1) 5
= 3 + 5n
Hope this helps
In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
The partial quotient is 23
5.B
6.D
7.A
8.B
9.A
10.C hsvs whehsg
