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3 years ago

What is the 7th term in the geometric sequence described by this explicit formula?an = –3 • (3)(n – 1)

Mathematics

2 answers:

Genrish500 [490]3 years ago

7 0

Answer:

7th term is -2187

Step-by-step explanation:

Nth term of the geometric sequence is given by

$a_n = a_1(r)^{n-1}$

where a1 is the first term and 'r' is the common ratio

$a_n = -3(3)^{n-1}$

a1=-3 and r=3

7 th term of the geometric sequence is

$a_7 = a_1(r)^{6}$

replace the values of a1 and 'r'

$a_7 = -3(3)^{6}$

a_7=-2187

I am Lyosha [343]3 years ago

3 0

Answer:

7th term = -2187

Step-by-step explanation:

The formula for nth term of a geometric sequence is given by:

$a_n=a*r^{n-1}$

Where

a is the first term,
r is the common ratio,
n is the nth term (term number)

Since the question gives us the formula and wants to know 7th term, we just plug in 7 into n:

$a_n=(-3)*(3)^{n-1}\\a_n=(-3)*(3)^{7-1}\\a_n=(-3)*(3)^6\\a_n=-2187$

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Answer:

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Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

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