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laiz [17]
3 years ago
8

Which expression is equivalent to V8x7y8 ?

Mathematics
2 answers:
8090 [49]3 years ago
6 0

Answer:

the third one

Step-by-step explanation:

Iteru [2.4K]3 years ago
4 0
The answer is C!
good luck!
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A football is kicked from the ground and follows the graph of the function y = –t2 + 3t, where y represents height and t represe
vesna_86 [32]

Answer:

The height of the objects are the same after 2 seconds.

Step-by-step explanation:

In order to calculate at which time both objects have the same height we need to find the value of t that makes both equations equal. Therefore:

-t^2 + 3t = -t + 4\\t^2 - 3t - t + 4 = 0\\t^2 - 4t + 4 = 0\\t_{1,2} = \frac{-(-4) \pm \sqrt{(-4)^2 - 4*1*4}}{2*1} = \frac{4 \pm \sqrt{16 - 16}}{2}\\t_{1,2} = \frac{4}{2} = 2

The height of the objects are the same after 2 seconds.

8 0
3 years ago
Which pair is made up of prime numbers 11 & 33 , 42 & 56 , 37 & 67, 57 & 97
Cerrena [4.2K]

Answer:

37 & 67

Step-by-step explanation:

11 & 33

  • 11 - 1, 11
  • 11 is prime
  • 33 - 1, 3, 11, 33
  • 33 is composite number
  • 11 & 33 is incorrect

42 & 56

  • 42 - 1, 2, 3, 6, 7, 14, 21, 42
  • 56 - 1, 2, 4, 7, 8, 14, 28, 56
  • Both 42 and 56 are composite numbers
  • 42 & 56 is incorrect

37 & 67

  • 37 - 1, 37
  • 67 - 1, 67
  • Both 37 and 67 are prime numbers
  • 37 & 56 is correct

57 & 97

  • 57 - 1, 3, 19, 57
  • 97 - 1, 97
  • 57 is a composite number, 97 is a prime number
  • 57 & 97 is incorrect
3 0
3 years ago
Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview
mario62 [17]

Answer:  The required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

Step-by-step explanation:   We are given to solve the following differential equation :

5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.

So, the general solution of the given equation is

y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.

Differentiating with respect to t, we get

y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.

According to the given conditions, we have

y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

and

y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.

From equation (ii), we get

B=\dfrac{7}{3}.

Thus, the required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

7 0
3 years ago
 The difference between the product of four and a number and six
Olin [163]
Answer- 4x-6
explain- i got it right
5 0
3 years ago
If 7(x-7)=-15 then x =
soldi70 [24.7K]

7(x-7)=-15

distribute

7x-49 =-15

add 49 to each side

7x =34

divide by 7

x = 34/7

x = 4 6/7

6 0
3 years ago
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