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IRINA_888 [86]
3 years ago
10

For the following questions answer independent, dependent, or both. a) This probability causes you to subtract one from the tota

l on the second draw because you don't replace. b) This probability causes you to multiply the probability of the first event by the probability of the second event. c) This probability causes you to leave the total the same on the second draw because you replace.
Mathematics
1 answer:
Elden [556K]3 years ago
7 0

Answer:

(a)Dependent

(b)Both

(c)Independent

Step-by-step explanation:

a) When selections are made without replacement, the second(next) outcome is dependent of the first(previous) outcome. Therefore, we subtract one from the draw on the total.

  • Dependent

(b)The probability of Event A and Event B is the multiplication of the probability of event A and the probability of event B. Events A and B can either be dependent or independent.

  • Both

(c)When selections are made with replacement, the next outcome is independent of the previous outcome. Therefore, we say that the two events are independent.

  • Independent
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Write 420 as a product 9f prime numbers​
stich3 [128]

Answer:

2, 2, 3, 5, 7 that is the farthest you can go

Step-by-step explanation:

2,2,3,5,7 prime factorization of 420 but impossible to get 9 factors

5 0
3 years ago
Here are 946 milliliters in a quart. There are 22 pints in a quart. How many milliliters are in a pint?
Fed [463]

Answer:  The answer is 43.


Step-by-step explanation:  Given that there is a quart, in which there are 946 millilitres and 22 pints. We are to find how many millilitres are there in a pint.

For that, we just need to divide number of milliliters by the number of pints in the quart.

Let us start as follows -

In 22 pints of the quart = 946 millilitres.

Therefore, in 1 pint of the quart = 946/22 = 43 millilitres.



6 0
3 years ago
Read 2 more answers
Can somebody explain to me how they got 3^4(x) = 3^3(x+2)? Then explain what happened to the 3 in 3^4 and the 3 in 3^3? Please a
musickatia [10]

Answer:

x=6

Step-by-step explanation:

81^x = 27 ^(x+2)

81 = 3^4    and 27 =3^3  so replace 81 and 27 in the equation

3^4^x = 3^3^(x+2)

When we have a power to a power we can multiply the exponents

a ^b^c = a^(b*c)

3^(4x) = 3^(3*(x+2))

Since the bases are the same, the exponents  have to be the same

a^b = a^c   means b=c

4x = 3(x+2)

Now we can solve for x

Distribute

4x = 3x+6

Subtract 3x from each side

4x-3x = 3x-3x+6

x = 6

3 0
4 years ago
Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]

The left and right endpoints of the i-th subinterval, respectively, are

\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8

r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8

for 1\le i\le4, and the respective midpoints are

m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8

  • Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}

  • Midpoint rule

We approximate the area for each subinterval by

M_i=f(m_i)(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}

  • Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial p_i(x), where

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It so happens that the integral of p_i(x) reduces nicely to the form you're probably more familiar with,

S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))

Then the integral is approximately

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0
3 years ago
PLZ HELP ASAP I WILL GIVE BRAINIEST TO FIRST PERSON TO ANSWER. question: Tahmar knows the formula for simple interest is I = Prt
Gre4nikov [31]
P=I/RT
P=20/(0.05*5)
P=20/(0.25)
P=80

It is $80
3 0
3 years ago
Read 2 more answers
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