Fraction form: x=7/12
Steps:
64^4x-3
2^6(4x-3)=2^-4
6(4x-3)=-4
4x-3=-2/3
4x=7/3
X=7/12
Answer:
Step-by-step explanation:
Cross multiply,
y(x - 8) = x +3
yx - 8y = x + 3
yx - 8y -x = 3
yx - x = 3 + 8y
(y - 1)x = 3 +8y
The probability of choosing cards either Q or R when a card is drawn from a deck of 8 cards is 0.25.
Given that a card is randomly chosen from 8 cards shown in figure.
We have to calculate the probability of choosing either Q or R when a card is drawn from those 8 cards.
Probability means calculating the likeliness of happening an event among all the events possible. It lies between 0 and 1. It cannot be negative.
Number of cards=8
Number of repeated cards=0
Number of cards showing Q and R =1 each.
Probability of getting Q or R is P(X=Q)+P(X=R)
= 1/8+1/8
=2/8
=1/4
=0.25
Hence the probability of getting either P or Q when a card is drawn from 8 cards is 0.25.
Learn more about probability at brainly.com/question/24756209
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The solution (x,y) needs to work in both equations. With multiple choice you can do guess and test method. Otherwise you need to combine the two equations into one by substitution or elimination methods.
21. substitution works well here since one equation is y= x+3. you can easily substitute the (x+3) for y in the other equation.
2x + (x+3) = -6
3x + 3 = -6
3x = -9
x = -3
use this in either equation to find y.
y = (-3)+3
solution: (-3,0)
22. these both equal y so they equal each other.
4x - 1 = 3x +6
4x - 3x = 6 + 1
x = 7
use this in either equation to find y
y = 4(7) - 1
y = 28 - 1
y = 27
solution: (7,27)
23. one equation is y = 2x - 3. So substitute (2x -3) for y in the other equation.
4x = 2(2x - 3) + 6
4x = 4x - 6 + 6
4x = 4x
x = x
any solution will work, infinitely many.
24. infinitely many solutions means the two equations are the same equation. Like the previous one they didn't look the same but if you put them both in terms of y...
y= 2x-3
4x = 2y + 6
4x - 6 = 2y
(4x - 6)/2 = y
2x - 3 = y
same equation.
from the image, I can't see all options but A & C do not look like the same equations. It's got to be either B or D.
