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balu736 [363]
4 years ago
8

Part of a tiling design is shown. The center is a regular hexagon. A square is on each side of the hexagon, and an equilateral t

riangle joins the squares. Complete the pattern around the hexagon and calculate the total area of the pattern.
A.
403.1 in.
B.
503.1 in.
C.
1,119.6 in.
D.
1,379.4 in.
Mathematics
1 answer:
VMariaS [17]4 years ago
8 0

1,119.6 in. the answer is c my diddle.


Find the area of the hexagon which is 259.81

Find the area of the squares which is (6)100

Find the area of the triangles which was (6)43.3

259.81 + 600 + 259.8

519.6 + 600 = 1119.6

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How many 4 digit multiples can not be divided by 5
Advocard [28]

Answer:

1800

Step-by-step explanation:

Let us solve this question by Modular Airthmatic.

Let the lowest 4 digit number be X.

X= 1 (mod 5)

X =2 (mod 5)

X=3 (mod 5)

X =4 (mod 5)

X=1+5 t where t is any integer.

1+5 t=2 (mod 5)

5 t=1 (mod 5 )

5 is the Modular Inverse of modulo 5

t=1 (mod 5)

t =1+5 u : u= any integer.

X becomes 1+ 5 (1+5u )=6+25 u

6+25u =3 (mod 5)

25 u= -3 (mod 5)=2 (mod 5)

25 is Modular Inverse of Modulo 5

u=2 (mod 5)

u =2+5 v : v= any integer.

X becomes 6 +25 (2+5 v)=56+125 v .

56 +125 v=4 (mod 5)

125 v=-52 (mod 5)=3 (mod 5)

125 is Modular Inverse of modulo 5

v = 3 (mod 5)

v =3 +5 w where w is any integer.

For lowest 4 digit number, take

w=200

X=1003 : Lowest 4 digit number.

Take w=201

X=208 : Next number.

For 4 digit largest number, take

w=1995

X= 9978 : Largest number.

No. of Numbers =(1995 - 200 )+1=1800 □Ans.

8 0
3 years ago
Read 2 more answers
Can you help me on both of this problems
AlekseyPX

Answer:

9. Option D, 2(3x + 5) and 6x + 10

10. 9 + 3 (10÷2) - 5² = -1

Hope this helps!

7 0
3 years ago
Read 2 more answers
For the pair of supply-and-demand equations, where x represents the quantity demanded in units of 1000 and p is the unit price i
Liono4ka [1.6K]

Answer:

7 and 6 respectively

Step-by-step explanation:

Firstly, we have to solve the equations simultaneously.

2x + 7p = 56

3x - 11p = -45

Multiply equation I by 3 and ii by 2

6x +21p = 168

6x - 22p = -90

Subtract the second from first to yield:

43p = 258

p = 6

Insert this in equation 1 where we have 2x + 7p = 56

2x + 7(6) =56

2x + 42 = 56

2x = 14 and x = 7

The equilibrium price is 6 and the equilibrium quantity is 7

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Solve for the variable of x.<br><br> 2y = x + 36p
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Answer:

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Step-by-step explanation:

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