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DENIUS [597]
3 years ago
6

If you wanted the pitch of a horn to drop relative to an observer, which way would you move the horn, relative to where that obs

erver is located?
A.Leave it in the same place and play the horn more softly


B.Away from the observer


C.Towards the observer
Physics
2 answers:
mel-nik [20]3 years ago
5 0

Answer: The correct option is B

Explanation:

In Doppler effect, there is an apparent change in the frequency when there is a relative motion between the source and the listener.

Pitch depends on the frequency.

When the source and the listener are moving away from each other then there is decrease in the frequency. In this case, the pitch will be lower.

In the given problem, to drop the pitch of the horn relative to an observer, you would move the horn away from the observer.

Therefore, the correct answer is "Away from the observer".

Ratling [72]3 years ago
4 0
(B) Away from the observer. 
The closer- the higher
The farther- the lower

You might be interested in
Why pressure above the surface is greater than in the air​
nexus9112 [7]

Answer:

At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels. ... Since most of the atmosphere's molecules are held close to the earth's surface by the force of gravity, air pressure decreases rapidly at first, then more slowly at higher levels.

Explanation:

7 0
3 years ago
What is the net force exerted by these two charges on a third charge q3 = 49.5 nC placed between q1 and q2 at x3 = -1.170 m ? Yo
insens350 [35]

Full Question

Consider two point charges located on the x axis: one charge, Q1 = -12.0 nC , is located at x1 = -1.705m ; the second charge, Q2 = 36.5 nC, is at the origin (x=0.0000).

What is the net force exerted by these two charges on a third charge q3 = 49.5 nC placed between q1 and q2 at x3 = -1.170 m ? Your answer may be positive or negative, depending on the direction of the force.

Answer:

6.79E6 N

Explanation:

Given

Q1 is negative and to the left of Q3 the force will be to the left

Q2 is positive and to the right of Q3 the the force will also be to the left

Net Force is calculated as:

Using Coulomb's law

Coulomb's law: F = kqQ / r²

the constant k = 8.99 x 10^9 N m2 / C2

F = -kQ1*Q3/(r1)² -kQ2*Q3/(r2)²)

F = -kQ3(Q1/(r1)² + Q2/(r2)²)

Where

Q1 = -12nC = -12 * 10^-9C

Q2 = 36.5nC = 36.5 * 10^-9C

Q3 = 49.5nC = 49.5 * 10^-9C

x1 = -1.705m

x2 = x = 0

x3 = -1.170m

r1 = x3 - x1

r1 = -1.170 - -1.705

r1 = -1.170 + 1.705

r1 = 0.535

r1² = 0.286225

r2 = x3

r2 = -1.170

r2² = -1.170²

r2² = 1.3689

So,

F = (-8.99 * 10^9)(49.5 *10^-9) [-12 * 10^-9/0.286225 + 36.5 * 10^-9/1.3689]

F = -445.005 (−4.192505895711E−8 + 2.6663744612462E−8)

F = -445.005 * −1.5261314344648E−8

F = -(8.99 * 10^9) * (49.5 * 10^-9) * [ (-12 * 10^-9) /(-1.770 - -1.705)² + (36.5 * 10^-9)/(-1.170)²]

F = -445.005( −0.000002813572941777538)

F = 0.00000679136118994008324

F = 6.79E6 N

3 0
3 years ago
I need help can someone help me pls
pychu [463]

Answer:

copper

Explanation:

4 0
3 years ago
Read 2 more answers
A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to
goblinko [34]
Oh my lord lol I was do ready to help then I saw numbers
4 0
3 years ago
URGENT HELP PLEASE, GIVING BRAINLIEST IF YOU ANSWER CORRECTLY!! (20 pts!!)
Kobotan [32]
The answer is c 1386j

This calculator is very helpful I use it on my homework

https://www.omnicalculator.com/physics/specific-heat
8 0
2 years ago
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