"Oscilloscope" can be used to show the shape of a sound wave
Hope this helps!
Answer: 1.3 *10^6 Ω*m
Explanation: In order to explain this problem we have to use the following expression for the resistence:
R=L/(σ*A) where L and A are the length and teh area for the wire, respectively. σ is the conductivity of teh Nichrome.
Then, from mteh OHM law we have V=R*I so R=V/I=2/3.2=0.625 Ω
Finally we have:
σ=L/(R*A)=1.3/(0.625*1.6*10^-6)=1.3*10^6 Ω*m
Answer:
10000 V
0.00225988700565 m²

Explanation:
E = Electric field = 
d = Gap = 2.5 mm
Q = Charge = 80 nC
= Permittivity of free space = 
Potential difference is given by

The potential difference between the plates is 10000 V
Area is given by

The area of the plate is 0.00225988700565 m²
Capacitance is given by

The capacitance is 
Answer:

Explanation:
In order to solve this problem, we can do an analysis of the energies involved in the system. Basically the addition of the initial potential energy of the spring and the kinetic energy of the mass should be the same as the addition of the final potential energy of the spring and the kinetic energy of the block. So we get the following equation:

In this case, since the block is moving from rest, the initial kinetic energy is zero. When the block loses contact with the spring, the final potential energy of the spring will be zero, so the equation simplifies to:

The initial potential energy of the spring is given by the equation:

the Kinetic energy of the block is then given by the equation:

so we can now set them both equal to each other, so we get:

This new equation can be simplified if we multiplied both sides of the equation by a 2, so we get:

so now we can solve this for the final velocity, so we get:

The wavelengths of the constituent travelling waves CANNOT be 400 cm.
The given parameters:
- <em>Length of the string, L = 100 cm</em>
<em />
The wavelengths of the constituent travelling waves is calculated as follows;

for first mode: n = 1

for second mode: n = 2

For the third mode: n = 3

For fourth mode: n = 4

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.
The complete question is below:
A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:
A. 400 cm
B. 200 cm
C. 100 cm
D. 67 cm
E. 50 cm
Learn more about wavelengths of travelling waves here: brainly.com/question/19249186