How many pounds of force must a guardrail’s top rail be able to withstand? A. 150 lbs. B. 200 lbs. C. 400 lbs. D. 5,000 lbs.
2 answers:
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Answer: 9.0 atm
Explanation:
To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:
where,
are initial pressure and volume.
are final pressure and volume.
We are given:
Putting values in above equation, we get:
Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm
Answer:
<em>The shortest distance to an object that this radar can detect would be </em>
<em>111 m</em>
Explanation:
The shortest distance is the minimum distance that would be detected by the radar, The time of oscillation can be obtained thus;
T = 1/f ..........1
but f= v/λ substituting f into equation 1 we have;
T = λ/v...............2
Where λ is the wavelength = 2.2 m
v is the velocity of light since the radar is an electromagnetic wave
= 3 x m/s
T = 2.2 m / 3 x m/s
T = 7.33 x s
<u>Calculating the time interval required by the pulse</u>
Since the interval of the pulse (t) is 100 times greater than the period of oscillation, the time of the pulse is expressed as;
t = 100 x T
t = 100 x 7.33 x s
t = 7.33 x s
Therefor the time of the pulse is 7.33 x s
<u>Calculating for the shortest distance of the radar</u>
The shortest distance of the radar can be obtained using the equation below;
λ_s = (t/2) x v ............3
Substituting into equation 3 we have
λ_s = (7.33 x /2) x 3 x
m/s
λ_s = 111 m
Therefore the shortest distance to an object that this radar can detect would be 111 m
Answer:
n = 19
Explanation:
= Wavelength of the light absorbed = 91.65 nm = 91.65 x 10⁻⁹ m
= nth level = n
= 1
Using conservation of energy