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4 years ago

A car starts from rest and reaches 20 m/s in 5 seconds. What’s the distance does the car travel.

Physics

1 answer:

Vanyuwa [196]4 years ago

4 0

Answer: 100

Explanation:duuuuuh

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alexdok [17]

Answer:

turtle

Explanation:

6 0

3 years ago

How much heat is needed to melt 13.74 kg of silver that is initially at 20°C?

salantis [7]

Answer:

$Q = 4.63 \times 10^6 J$

Explanation:

As we know that melting point of silver is

T = 961.8 degree C

Latent heat of fusion of silver is given as

L = 111 kJ/kg

specific heat capacity of silver is given as

$s = 240 J/kg C$

now we will have

$Q = ms\Delta T + mL$

$\Delta T = 961.8 - 20$

$\Delta T = 941.8 degree C$

now from above equation

$Q = (13.74)(240)(941.8) + (13.74)(111 \times 10^3)$

$Q = 3.1 \times 10^6 + 1.53 \times 10^6$

$Q = 4.63 \times 10^6 J$

3 0

3 years ago

London lives 1200 meters south of Chick-fil-A and is thinking about going there for lunch. When she is ready to leave, she reali

saul85 [17]

Answer:

1750 m

Explanation:

The distance traveled is the 750 meters to the Aunt's house plus the 1000 m from there to Chick-fil-A.

750 +1000 = 1750 . . . meters traveled

6 0

3 years ago

If length of wire is doubled keeping the diameter constant ,its Youngs modulus will be

Luda [366]

Answer:

Y = Stress / Strain = (F / A) / (l / L) where l is the change in length

Since L is doubled and A remains the same one would expect l, the change in length to also double so Y remains the same.

As an example think of hanging a weight from a spring and the same weight from a similar spring of twice the length - one would expect the longer spring to show twice the extension of the shorter spring.

3 0

3 years ago

To determine the pressure in a fluid at a given depth with the air-filled cartesian diver, we can employ Boyle's law, which stat

aniked [119]

Answer:

The pressure at this depth is $1.235\cdot P_{atm}$ .

Explanation:

According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:

$\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}$ (1)

Where:

$V_{1}, V_{2}$ - Initial and final volume.

$P_{1}, P_{2}$ - Initial and final pressure.

If we know that $V_{2} = 0.81\cdot V_{1}$ , then the pressure ratio is:

$\frac{P_{2}}{P_{1}} = 1.235$

If $P_{1} = P_{atm}$ , then the final pressure of the gas is:

$P_{2} = 1.235\cdot P_{atm}$

The pressure at this depth is $1.235\cdot P_{atm}$ .

6 0

3 years ago