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bonufazy [111]
3 years ago
14

Help me i cant solve it

Physics
1 answer:
Tomtit [17]3 years ago
5 0
<h2>================</h2><h2><em>hope it helps you see the attachment for further information.... </em></h2>

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<h3><em>mark </em><em>it </em><em>as </em><em>brainliest</em><em>.</em><em>.</em><em>.</em><em>. </em><em>✌</em><em>✌</em></h3>

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C . All of the different types of electromagnetic waves

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Which of the following are examples of projectile motion?
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A spring hangs from the ceiling with an unstretched length of x 0 = 0.35 m . A m 1 = 6.3 kg block is hung from the spring, causi
Jlenok [28]

Answer:

x₂=0.44m

Explanation:

First, we calculate the length the spring is stretch when the first block is hung from it:

\Delta x_1=0.50m-0.35m=0.15m

Now, since the stretched spring is in equilibrium, we have that the spring restoring force must be equal to the weight of the block:

k\Delta x_1=m_1g

Solving for the spring constant k, we get:

k=\frac{m_1g}{\Delta x_1}\\\\k=\frac{(6.3kg)(9.8m/s^{2})}{0.15m}=410\frac{N}{m}

Next, we use the same relationship, but for the second block, to find the value of the stretched length:

k\Delta x_2=m_2g\\\\\Delta x_2=\frac{m_2g}{k}\\\\\implies \Delta x_2=\frac{(3.7kg)(9.8m/s^{2})}{410N/m}=0.088m

Finally, we sum this to the unstretched length to obtain the length of the spring:

x_2=0.35m+0.088m=0.44m

In words, the length of the spring when the second block is hung from it, is 0.44m.

3 0
4 years ago
.
Sergio039 [100]

Answer:

The correct answer is B

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