A probability contour represents a bounded, finite volume about a nucleus in which there is a substantial probability of finding the electron is TRUE.
The rectangular of the wave characteristic, ψ2 , represents the opportunity of locating an electron in a given vicinity within the atom. probability finding electron at nucleus is zero.
An orbital is a mathematical feature that has a fee at all points in space. The magnitude squared of that fee is the chance according to volume of locating an electron in that volume of area.
The probability of locating electron in nodes is 0, but there are electron densities on all round nodes. The node is a point or a floor (relying at the type of node) so the volume of the vicinity wherein ψ=zero is zero. we want to position V=zero and we get P=zero so the chance of finding the electron on the node is zero.
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Answer:
A probe charge
Explanation:
As we know that electric field intensity is the force experienced by the probe charge which is placed in the electric field region
Here we can say it as
so here that probe charge should be very small so that it will not disturb the electric field in the space.
If the probe charge is of large magnitude then the field will get disturbed and the intensity which is to be measured is different from its actual value.
Also the sign of the probe charge is taken to be positive.
so correct answer here will be
A probe charge
