It's 16,875
Hope I helped! ( Smiles )
Answer:
The induced current is 0.084 A
Explanation:
the area given by the exercise is
A = 200 cm^2 = 200x10^-4 m^2
R = 5 Ω
N = 7 turns
The formula of the emf induced according to Faraday's law is equal to:
ε = (-N * dφ)/dt = (N*(b2-b1)*A)/dt
Replacing values:
ε = (7*(38 - 14) * (200x10^-4))/8x10^-3 = 0.42 V
the induced current is equal to:
I = ε /R = 0.42/5 = 0.084 A
It’s b because a spring of negligible mass then if u multiply
The sphere has a constant potential. It is the electric field.

In the sphere, then

Outside the sphere, then

The elements of the electric field include

Which becomes,

<h3>
In a consistent electric field, is force constant?</h3>
Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.
If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).
A torque is experienced by an electric dipole (p) in an even electric field (E). The vector cross product of p and E determines the torque's direction.
To learn more about uniform electric field, visit
brainly.com/question/17426130
#SPJ4
Answer:
c) 10.7m/s
Explanation:
From the exercise we know that at 5m the ball is traveling at 4m/s
To calculate its initial velocity we need to solve the following equation:

Since the initial height is 0
Solving for 
