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WARRIOR [948]
3 years ago
8

1+3+5+7+...+1003= what is the answer?

Mathematics
2 answers:
Charra [1.4K]3 years ago
4 0
1+(n-1)d = 1003
(n-1)2 = 1002
n-1 = 501
n=502
Sum = 502(1+1003)/2 = 253,004
sergij07 [2.7K]3 years ago
3 0
<span>a) 1 +2 +3 +4 +......+98
98 +97 +96 +95+......+1
sum 99 +99 +99 +99+......+99
there are 98 of these sums, the total is 98 * 99 = 9702, since this sum is twice the sum of the numbers 1 thru 98, we have
sum 1 +2 +3 +4 +.....98 = 9702/2 = 4851

b) 1 +3 +5 +7+.....+1003
1003 +1001 + 999 +997 +....+1
sum 1004 +1004 +1004 +1004 +..1004
There are 502 of these sums. the total is 502 * 1004 = 504008, since this sum is twice the sum of the numbers 1 +3 +5 +7 +....1003, we have
sum 1 +3 +5 +7+.....+1003 = 504008/2 = 252004</span>
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sukhopar [10]

Answer:

The found values are:

A = 1/3

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Step-by-step explanation:

We know that general equation is given by:

y = mx + c

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x + 3y = -5

y = -(1/3)x - 1/3(5)

Slop of the equation is -(1/3). As parallel line have same slope substitute it in the first equation:

Ax + By = 3

By = -Ax - 3

By = (1/3)x - 3

Hence, A = 1/3

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B(2) = (1/3)(-7) -3

B(2) = -7/3 - 3

B(2) = -16/3

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4 0
3 years ago
A species of phytoplankton measures about 2 × 10−6 in. A grain of sand measures about 1 × 10−4 in. About how many times longer i
taurus [48]

Answer : The grain of sand is 50 times greater than the phytoplankton.

Step-by-step explanation :

As we are given that:

Size of phytoplankton = 2 × 10⁻⁶ in

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Now we have to determine how many times longer the grain of sand is than the phytoplankton.

We are dividing the sand grain size by the phytoplankton size.

This can be done by equating it as follows:

\frac{\text{Size of sand grain}}{\text{Size of phytoplankton}}=\frac{1\times 10^{-4}in}{2\times 10^{-6}in}

\frac{\text{Size of sand grain}}{\text{Size of phytoplankton}}=50

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5 0
3 years ago
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hope this helps

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4 years ago
Point T is on line segment
Fofino [41]

Answer:

Numerical length of TU = 6

Step-by-step explanation:

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5x = 4x+2x-3

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4 0
3 years ago
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