Step-by-step answer:
The domain of log functions (any legitimate base) requires that the argument evaluates to a positive real number.
For example, the domain of log(4x) will remain positive when x>0.
The domain of log_4(x+3) requires that x+3 >0, i.e. x>-3.
Finally, the domain of log_2(x-3) is such that x-3>0, or x>3.
x=6 , y = 4
Step-by-step explanation:
( x-2,6)=(4,Y+2)
this means; (x-2) &( 4) stands for" x "axis.
and( 6 )& (y+2) stands for y axis.
So, we can say( x-2)=X1 & (4)=X2 , (6)=Y1 & (y+2)=Y2
then; to Solve The Equation we use The Formula: X1=X2 for "X" And Y1=Y2 for "Y".
Solution: for "X" ; X1=X2
x-2= 4
x=4+2
x=<u>6</u>
For "Y" ; Y1=Y2
6 = y+2
y=6-2
y=<u>4</u>
finally check ; ( (x-2),6) = (4,(y+2) )
(6-2),6 = (4,(4+2) )
( (4),6) = (4,(6) )
(4,6) = (4,6)
so, X1 =X2 ; 4 = 4
Y1 = Y2 ; 6 = 6
Answer:
x = 0
Step-by-step explanation:
Q(1, 2 ) and Q1(- 1, 2 ) are both 1 unit from the y- axis
Q is 1 unit to the right of the y- axis and Q1 is 1 unit is 1 unit to the left of the y-axis, thus
The y- axis is the mirror line with equation x = 0
Answer:
its nine degrees
Step-by-step explanation:
this is also 5 pts btw