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djyliett [7]
2 years ago
10

If Lonnie has 40 plants and half of his plants die...how many plants does that

Mathematics
2 answers:
Veseljchak [2.6K]2 years ago
4 0

Answer:

20

Step-by-step explanation:

We know that she initially had 40 plants. The half of 40 is 20. That is also the number of plants that died.

dem82 [27]2 years ago
3 0

Answer: A. 20

Step-by-step explanation:

<u>Given Information:</u>

Original = 40 Plants

New = Half Died

<u>Find the number of plants that died:</u>

40 × (1 / 2) = 40 / 2 = 20 Plants

or

40 ÷ 2 = 20 Plants

Therefore, it equals to \boxed{20 \:Plants}

Hope this help!! :)

Please let me know if you have any questions

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Please help me with this im not good in math i have no brain
Tanzania [10]
The answer is the first one. I am pretty sure.
4 0
3 years ago
Please can someone help me with this !!!!!!!
Anvisha [2.4K]

Answer: 1 : 20%

2 : 80%

3 : -90% (negative 90%), if no negatives are allowed, than it is a 90% decrease.

4 : $90

5: $31.50

Step-by-step explanation:

4 0
4 years ago
Ellen said she spent half her money for lunch and half of what was left for a movie. She now has $1.20. How much did she spend f
goldenfox [79]

Answer: She spend $1.20 for lunch.

Step-by-step explanation:

Let the total amount be 'x'.

Half of her money spend for lunch be \dfrac{x}{2}

Half of her money left for a movie be \dfrac{x}{2}

Amount she has now = $1.20

So, According to question, it becomes ,

\dfrac{x}{2}=1.20\\\\x=1.20\times 2\\\\x=\$2.40

Hence, Amount she spend for lunch is \dfrac{x}{2}=\dfrac{2.40}{2}=\$1.20

Therefore, she spend $1.20 for lunch.

8 0
3 years ago
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard d
Misha Larkins [42]

Answer:

14.69% probability that defect length is at most 20 mm

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 28, \sigma = 7.6

What is the probability that defect length is at most 20 mm

This is the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 28}{7.6}

Z = -1.05

Z = -1.05 has a pvalue of 0.1469

14.69% probability that defect length is at most 20 mm

5 0
4 years ago
Please answer this one question!
Dvinal [7]

Answer:

i did this it linear im pretty sure

6 0
3 years ago
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