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pantera1 [17]
3 years ago
8

Write an expression for the potential energy of a body of mass m in the gravitational field of the earth and moon. let me be the

earth's mass, mm the moon's mass (where 81 m m e m = ), r the distance from the earth's center, and r the physics 113p, summer 2015 study guide module 9 © 2015 university of rochester 4 all rights reserved distance from the moon's center. the distance between earth and moon is about 384,400 km.
Physics
1 answer:
TEA [102]3 years ago
3 0
Attraction forces subtract one to each other....and there is a point where such forces are perfectly equal...such point is such that its distance from earth c.o.m. is √81 = 9.00 times greater than its distance from moon c.o.m. 
Generic point gravity g can be evaluated this way 
ge = Me*G/de^2 
gm = Mm*G/(3.844*10*8-de)^2 
g = ge-gm 
ge/gm = 81*(1-d)^2/d^2 
if ge/gm = 1, then : 
de^2 = 81(1-de)^2
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PLEASEE HELPPLook at the diagram of two students pulling a bag of volleyball equipment. The friction force between the bag and t
mars1129 [50]

Answer:

The net force is 21 N, and the bag will go to the right.

Explanation:

You can find the net force by adding both values of the boy and the girl, and then subtracting four from it. You can also figure out which direction its moving by looking at which side is exerting the most force, which would be the right side.

<em>Hope </em><em>it </em><em>helps</em><em>!</em>

7 0
3 years ago
A woman (mass= 50.5 kg) jumps off of the ground, and comes back down to the ground at a velocity of -8.4 m/s.
Blizzard [7]

Answer:

Approximately 1.6\times 10^{3}\; \rm N.

Explanation:

By the Impulse-Momentum Theorem, the change in this woman's momentum  will be equal to the impulse that is applied to her.

The momentum p of an object is equal to the product of its mass m and velocity v. That is: p = m \cdot v.

Let v(\text{before}) and v(\text{after}) represent the velocity of the woman before and after the landing. Let m represent the woman's mass.

  • The woman's momentum before the landing would be m \cdot v(\text{before}).
  • The woman's momentum after the landing would be m \cdot v(\text{after}).

Therefore, the change in this woman's momentum would be:

\begin{aligned}& \Delta p \\ & = p(\text{after}) - p(\text{before}) \\ &= m \cdot (v(\text{after})- v(\text{before}))\end{aligned}.

On the other hand, impulse is equal to force multiplied by the duration of the force. Let F represent the average force on the woman. The impulse on her during the landing would be F \cdot t.

Apply the Impulse-Momentum Theorem.

  • Impulse: F\cdot t.
  • Change in momentum: m \cdot (v(\text{after})- v(\text{before})).

Impulse is equal to the change in momentum:

F \cdot t = m \cdot (v(\text{after})- v(\text{before})).

After landing, the woman comes to a stop. Her velocity would become zero. Therefore, v(\text{after}) = 0\; \rm m \cdot s^{-1}.

\begin{aligned}F &= \displaystyle \frac{m \cdot (v(\text{after})- v(\text{before}))}{t} \\ &= \frac{50.5\; \text{kg} \times \left(0 \; \mathrm{m \cdot s^{-1}}- 8.4\; \mathrm{m \cdot s^{-1}}\right)}{0.27\; \rm s} \\ &\approx 1.6 \times 10^{3}\; \rm N\end{aligned}.

3 0
4 years ago
A cameraman sitting near the open door of a news helicopter accidentally drops his 140-g mobile phone out
Agata [3.3K]

Answer:B.140 m/s

Explanation:

4 0
4 years ago
Read 2 more answers
What type of wave vibrates parallel to the direction of travel
Irina-Kira [14]

Answer: Longitudinal waves

Explanation: For a sound wave traveling through air, the vibrations of the particles are best described as longitudinal. Longitudinal waves are waves in which the motion of the individual particles of the medium is in a direction that is parallel to the direction of energy transport

5 0
3 years ago
A person pushes a block 4 m with a force of 25 N. How much work is being done?
Elina [12.6K]

Answer:

<h2>100 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 25 × 4

We have the final answer as

<h3>100 J</h3>

Hope this helps you

3 0
3 years ago
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